如何用c ++创建结果空间 [英] how to make space in result with c++

问题描述

  #include     stdafx.h 
   #include   <   iostream  >  
  使用 命名空间标准; 
 
  int  main（）
 {
  int  A，bو，C; 
 cout<<  输入第一个数字：; 
 cin>> a; 
 cout<<  输入第二个数字：; 
 cin>> b; 
 
 c = a * b; 
 
 cout<<  结果为：<< c; 
 
} 

当c = a * b

a = 75

b = 86



注意。结果将显示为这样的6540

但是我想在这个数字之间留出空间6 5 4 0; nubmer之间的空格如何可以

解决方案

< blockquote>类似C的方法是：

 ... 
  const   int  size =  20 ; 
  char  buffer [size]; 
  int  n = snprintf（缓冲区，大小， ％d，c）;  //  使用安全功能：s  n  printf，不要使用sprintf  
断言（n> =  0 ）;  //  格式错误由负值表示 
 assert（n< size）;  //   n是写入的字符数，不包括终止空字符 
 的类=code-keyword>（ int  i =  0 ; i< n; ++ i）cout<< buffer [i]<< ' '; 

它的作用：

1）将 c 写入字符数组（ buffer ）。

2）确保你没有写过缓冲区末尾（使用 snprintf [ ^ ]）

3）make确保转换不需要比缓冲区提供的更多字符（请记入返回值并断言 [ ^ ]写作并不期望更大的缓冲区）。

4）最后写下每个字符后跟一个空格



类似C ++的方法是使用osstreamstream [ ^ ]。

 ... 
 ostringstream oss; 
 oss<< C; 
断言（oss.good（））;  //  无格式错误 
  //   C ++ 11版本 
  for （ char  ch：oss.str（））cout<< ch<< ' '; 
  //  基于迭代器的版本 
 string s = oss.str（）; 
  for （string :: iterator it = s.begin（）; it！= s.end（）; ++ it）cout<< *它<< ' '; 

干杯
Andi

转换为字符串（提示：查看 sprintf ）然后遍历输出每个字符后跟空格的字符。 />
问候，

Ian。

#include "stdafx.h"
#include <iostream>
using namespace std;

int main ()
{
    int a,bو,c;
    cout<<"Enter the First Number : ";
    cin>>a;
    cout<<"Enter the Second Number : ";
    cin>>b;

    c=a*b;

    cout<< "The Result is : "<<c;

}

when c=a*b
a = 75
b = 86

attention. the result will appear like this 6540
but i want space between the number like this 6 5 4 0 ;OK space between nubmer how can

解决方案

A C-like approach was:

...
const int size = 20;
char buffer[size];
int n = snprintf(buffer, size, "%d", c); // use the safe function: snprintf, do not use sprintf
assert(n >= 0);   // format error is indicated by a negative value
assert(n < size); // n is the number of characters written, excluding the terminating null-character
for(int i = 0; i < n; ++i) cout << buffer[i] << ' ';

What it does:
1) write the c into a character array (buffer).
2) make sure you do not write past the buffer end (use snprintf[^])
3) make sure the conversion does not need more characters than provided by the buffer (take in count the return value and assert[^] that writing was not expecting a larger buffer).
4) finally write each character followed by a space

A C++ like approach was to use ostringstream[^].

...
ostringstream oss;
oss << c;
assert(oss.good()); // no format error
// C++11 version
for(char ch: oss.str()) cout << ch << ' ';
// iterator based version
string s = oss.str();
for(string::iterator it = s.begin(); it != s.end(); ++it) cout << *it << ' ';

Cheers
Andi

Convert to a string ( hint: look at sprintf ) then iterate through the characters outputting each one followed by a space.
Regards,
Ian.

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