if +%的问题。 [英] problem with if + %.
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问题描述
x = 32154
if(X%2)
错误无法将类型''int''隐式转换为''bool ''
x = 32154
if (X % 2)
Error Cannot implicitly convert type ''int'' to ''bool''
推荐答案
是的,在c#中,整数值表达式不被0隐式转换为bool == false
,0!= true
(就像c / c ++那样)。
通常,你会进行一些比较关于价值:
Yes, in c#, an integer valued expression will not be implicitly converted to bool with0 == false
,0 != true
(like c/c++ does).
Typically, you perform some comparison on the value:
int x = 32154;
if ((x % 2) == 0)
如果你只是检查偶数与奇数,只需检查低位(假设你是两个赞美的)架构):
If you are just checking for even vs. odd, just check the low order bit (assuming you''re on a twos-compliment architecture):
if ((x & 1) == 0) // x is even
if ((x & 1) == 1) // x is odd
我一直在考虑
if((x%2)== 0)
和我想要的是
if((x%2)== 1)
但tnx无论如何我很欣赏
i have been experamenting with
if ((x % 2) == 0)
and the ting i wanted is
if ((x % 2) == 1)
but tnx anyway i appreciate it
嗯......你们但它疯狂地看着这个!我正在使用C#!
hmm... yes but it is buging like crazy look at this !i am using C#!
Console.WriteLine("This is a program that calculates the gcd of some typed number");
int StartingNum = Convert.ToInt16(Console.ReadLine());
int NumForCalculate = StartingNum;
string gcd = ("");
int gathering = 1;
operation:
int x = 2;
operation2:
if ((NumForCalculate / x) == :see below:)
{
if (gcd == "")
gcd = ("" + x);
else
gcd = (gcd + "," + x);
NumForCalculate = (NumForCalculate / x);
gathering = gathering * x;
if (NumForCalculate <= 1)
goto end;
else
goto operation;
}
else
{
x++;
goto operation2;
}
end:
Console.WriteLine("gcd of integers {0} is {1}, and gathering this set of numbers is {2}", StartingNum, gcd, gathering);
Console.ReadKey();
如果我设置20
如果((NumForCalculate / x)== 1)
那么整数20的gcd是11,并且收集这组数字是11
if((NumForCalculate / x)== 0)
然后gcd的整数20是21,并收集这个一组数字是21
if i set 20
if ((NumForCalculate / x) == 1)
then gcd of integers 20 is 11, and gathering this set of numbers is 11
if ((NumForCalculate / x) == 0)
then gcd of integers 20 is 21, and gathering this set of numbers is 21
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