如何获取目录中的目录数？ [英] how can I get the number of directories in a directory?

问题描述

我正在尝试获取目录中的目录数，但我无法获得真实的结果。如果目录中有5个文件，其中2个是目录，我得到''y''5但它必须是2.

x = isdirectory（dirp）;我不确定是否将相关内容发送给函数。谢谢。

I am trying to get the number of directories in a directory but I cannot get the real result. If there are 5 files in directory and 2 of them are directories, I get ''y'' 5 but It must be 2.
x= isdirectory(dirp); I am not sure whether I send the corrent thing to the function.Thanks in advance.

int listFilesIndir(char *currDir) //Lists files in directory
{
    struct dirent *direntp;
    DIR *dirp;
    int x ,y =0 ;


    if ((dirp = opendir(currDir)) == NULL) 
    {
        perror ("Failed to open directory");
        return 1;
    }

    while ((direntp = readdir(dirp)) != NULL)
    {
        printf("%s\n", direntp->d_name);
        x= isdirectory(dirp); //I dont not know what I should send to the function 
                              // to check if its directory or not? it must 
                              // be ''dirp'' or ''d_name''? what?
        if(x != 0)
            y++;
    }
    printf("direc Num : %d\n",y );

    while ((closedir(dirp) == -1) && (errno == EINTR)) ;

    return 0;
}


int isdirectory(char *path) 
{
    struct stat statbuf;

    if (stat(path, &statbuf) == -1)
        return 0;
    else 
        return S_ISDIR(statbuf.st_mode);
}

推荐答案

我发现了问题。现在效果很好。 if statemenet已更新。

I have found the problem .Now It works great. The if statemenet is updated.

int listFilesIndir(char *currDir) 
{
    struct dirent *direntp;


    DIR *dirp;
    int x ,y =0 ;


    if ((dirp = opendir(currDir)) == NULL) 
    {
        perror ("Failed to open directory");
        return 1;
    }

    while ((direntp = readdir(dirp)) != NULL)
    {
        printf("%s\n", direntp->d_name);
        if(direntp->d_type == DT_DIR) //Updated..
            y++;
    }


    printf("direc Num (except parent and curr) : %d\n",y-2 );

    while ((closedir(dirp) == -1) && (errno == EINTR)) ;

    return 0;
}

这篇关于如何获取目录中的目录数？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！