列出目录并获取目录的名称 [英] List Directories and get the name of the Directory

问题描述

我正在尝试获取代码列出文件夹中的所有目录，将目录更改为该文件夹，并获取当前文件夹的名称。到目前为止，我的代码是下面的代码，并且在一分钟之内不起作用。我似乎正在获取父文件夹名称。

I am trying to get the code to list all the directories in a folder, change directory into that folder and get the name of the current folder. The code I have so far is below and isn't working at the minute. I seem to be getting the parent folder name.

import os

for directories in os.listdir(os.getcwd()): 
    dir = os.path.join('/home/user/workspace', directories)
    os.chdir(dir)
    current = os.path.dirname(dir)
    new = str(current).split("-")[0]
    print new

我还有文件夹中的其他文件，但我不想列出它们。我已经尝试了以下代码，但是我还没有工作。

I also have other files in the folder but I do not want to list them. I have tried the below code but I haven't got it working yet either.

for directories in os.path.isdir(os.listdir(os.getcwd())): 

任何人都可以看到我错了什么？

Can anyone see where I am going wrong?

谢谢

得到它的工作，但似乎有点儿。

Got it working but it seems a bit round about.

import os
os.chdir('/home/user/workspace')
all_subdirs = [d for d in os.listdir('.') if os.path.isdir(d)]
for dirs in all_subdirs:
    dir = os.path.join('/home/user/workspace', dirs)
    os.chdir(dir)
    current = os.getcwd()
    new = str(current).split("/")[4]
    print new

推荐答案

这将打印当前目录的所有子目录：

This will print all the subdirectories of the current directory:

print [name for name in os.listdir(".") if os.path.isdir(name)]

我不知道你在做什么与 split（ - ） ，但是这个代码可能会帮助您找到解决方案？

I'm not sure what you're doing with split("-"), but perhaps this code will help you find a solution?

如果您想要目录的完整路径名，请使用 abspath ：

If you want the full pathnames of the directories, use abspath:

print [os.path.abspath(name) for name in os.listdir(".") if os.path.isdir(name)]

请注意，这些代码段只会获得直接的子目录。如果你想要子子目录等等，你应该像其他人一样建议使用 walk 。

Note that these pieces of code will only get the immediate subdirectories. If you want sub-sub-directories and so on, you should use walk as others have suggested.

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