内置方式列出ruby目录中的目录 [英] Built in way to list directories in a directory in ruby

问题描述

是否有更干净的内置方式来做到这一点？

  ree> Pathname.new（ /路径/到）children.select {|即| e.directory} {地图|？开发| d.basename.to_s} 
 => [test1，test2] 
  

理想情况下，我想避免目录？调用

解决方案

从Chandra的答案开始，取决于是否需要完整路径，您可以使用

 目录['app / * /'] 
＃=> [app / controllers /，app / helpers /，app / metal /，app / models /，app / sweepers /，app / views /
 
 Dir ['app / * /']。map {| a | File.basename（a）} 
＃=> [控制器，助手，金属，模特儿，扫除者，意见] 
  

如果您使用Ruby> = 1.8.7，Chandra的答案也可以重写为

  Pathname.glob（' app / * /'）。map（&：basename）
＃你可以跳过.to_s，除非你不需要使用字符串
＃记住你可以随时使用路径名作为字符串大部分Ruby函数
＃或内插值
  

Is there a cleaner built-in way to do this?

ree> Pathname.new('/path/to').children.select{|e| e.directory?}.map{|d| d.basename.to_s}
 => ["test1", "test2"]

Ideally I would like to avoid the directory? call

解决方案

Starting from Chandra's answer, depending on whether you need or not the full path, you can use

Dir['app/*/']
# => ["app/controllers/", "app/helpers/", "app/metal/", "app/models/", "app/sweepers/", "app/views/"

Dir['app/*/'].map { |a| File.basename(a) }
# => ["controllers", "helpers", "metal", "models", "sweepers", "views"]

If you use Ruby >= 1.8.7, Chandra's answer can also be rewritten as

Pathname.glob('app/*/').map(&:basename)
# you can skip .to_s unless you don't need to work with strings
# remember you can always use a pathname as string for the most part of Ruby functions
# or interpolate the value

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