Unix C程序以递归方式列出目录 [英] Unix c program to list directories recursively
问题描述
我正在进行POSIX C学习练习,其中涉及递归地列出指定目录中的文件/文件夹.该程序接受一个或多个目录的参数.我可以列出初始目录的内容,但递归有问题.我为递归函数调用传递参数的方式有问题吗?
I am working on a POSIX C learning exercise that involves recursively listing files/folders in a specified directory. The program takes in as arguments of one or more directories. I can list the contents of the initial directory fine but having a problem with the recursion. Is something wrong with the way I am passing in the argument for the recursive function call?
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>
#include <fcntl.h>
#include <sys/stat.h>
#include <sys/types.h>
#include <dirent.h>
#include <errno.h>
#include <string.h>
void listdir(char *argv[])
{
DIR *mydirhandle;
struct dirent *mydirent;
struct stat statinfo;
int n = 1;
while(argv[n] != NULL)
{
if((mydirhandle = opendir(argv[n])) == NULL)
{
perror("opendir");
exit(1);
}
printf("%s/\n", argv[n]);
while((mydirent = readdir(mydirhandle)) != NULL)
{
if((strcmp(mydirent->d_name, ".") == 0) || (strcmp(mydirent->d_name, "..") == 0))
{
continue;
}
else
{
printf("\t%s\n", mydirent->d_name);
//check if next entry is a directory
if(mydirent->d_type == DT_DIR)
{
//is current directory being passed correctly here?
listdir(mydirent->d_name);
}
}
}
n++;
closedir(mydirhandle);
}
}
int main(int argc, char *argv[])
{
if(argc < 2)
{
printf("usage: %s <directory>\n", argv[0]);
return 0;
}
listdir(argv);
return 0;
}
推荐答案
打开警告将显示您在进行递归函数调用时传递了错误的类型.我只需要让listdir
接受一个char *
参数而不是char **
,然后在main
中使用一个for循环就可以遍历多个参数.
Turning on warnings will show that you're passing the wrong type when making the recursive function call. I would simply make listdir
take a char *
argument rather than char **
, and then use a for loop in main
to loop over multiple arguments if you need to.
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