Catch（...）无法捕获浮点异常 [英] Catch (...) fails to catch floating point exception

问题描述

我知道catch（...）应该捕获任何异常。但是，在下面的程序中，catch（...）无法捕获浮点（除以零）异常。

I understood that catch (...) was supposed to catch any exception. In the following program, however, catch (...) fails to catch a floating point (divide by zero) exception.

#include <iostream>
using namespace std;

int main () 
  {
    int top = 90;
    int bottom = 0;
    
    try
      {
        cout << "top / 2 = " << top / 2 << endl;
        cout << "top / bottom = " << top / bottom << endl;
      }
    catch ( ... ) 
      {
        cout << "We have a problem." << endl;
      }
    cout << "Done" << endl;
    return (0);
  }

C ++规范是否已更改，或者程序有问题？



非常感谢，



TCNM

Has the C++ specification changed, or is something wrong with the program?

Thank you very much,

TCNM

推荐答案

这里回答：

http://stackoverflow.com/questions/6121623/catching-exception-divide-by-zero [ ^ ]

如果你正在使用Visual Studio，那么有一个构建选项来打开/关闭浮点异常配置属性\ C / C ++ \Code生成，它至少会让它抛出（添加/ fp：除了命令行）。正是你必须抓住我不确定但是 catch（...）应该有效。正如Victor所说，虽然它不是标准的，但不便携。

If you''re using Visual Studio there is s build option to turn on/off floating point exceptions Configuration Properties\C/C++\Code Generation which will at least get it to throw ( adds /fp:except to comand line ). Exactly what you''d have to catch I''m not sure but catch(...) should work. As Victor indicates though it''s not standard so not portable.

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