try / catch块中未捕获的异常 [英] Uncaught exception in try/catch block

问题描述

一种方法对yaml文件执行递归扫描并解析它们，提取一些信息。我使用sfYamlParser来解析yaml。我在try块中附带了对parse（）的调用，并捕获Exception $ e，但是我仍然收到一个致命错误：未捕获的异常。

A method performs a recursive scan for yaml files and parses them, extracts some of the information. I use sfYamlParser to parse the yaml. I enclosed the call to parse() in a try block and catch "Exception $e" but I still get a "Fatal Error: uncaught exception.

try{
    $definition = $parser->parse(file_get_contents($filePath));//line 20
} catch(Exception $e) {
    throw new Exception("Parsing model definiion '$filePath' failed.", 0, $e);
}

堆栈跟踪中的片段：

...Indexer.php(20): sfYamlParser->parse('type: com...') #3 

为什么我的catch块没有捕获异常？
我确实期望异常冒泡，然后被我的方法捕获
该系统命名空间，但使用异常设置。

Why is the exception not caught by my catch block? I did expect the Exception to bubble up and then be caught in my method. The coe is namespaced but "use Exception" is set.

错误消息：

Fatal error</b>:  Uncaught exception 'InvalidArgumentException' with message 'Unable to parse line 30 (key;          true).' in [...]/packages/fabpot-yaml/sfYamlParser.php:265
Stack trace:
#0 [...]/packages/fabpot-yaml/sfYamlParser.php(201): sfYamlParser-&gt;parse('type:         s...')
#1 [...]/packages/fabpot-yaml/sfYamlParser.php(201): sfYamlParser-&gt;parse('explicitPrivile...')
#2 [...]/packages/hydra/source/com/daliaIT/hydra/Indexer.php(20): sfYamlParser-&gt;parse('type:       com...')
#3 [...]/packages/co3/source/com/daliaIT/co3/PathHelper.php(97): com\daliaIT\hydra\{closure}('packages/hPacks...')
#4 [...]/packages/hydra/source/com/daliaIT/hydra/Indexer.php(28): com\daliaIT\co3\PathHelper-&gt;scanCallback('packages/hPacks...', 'hmd', Object(Closure))

编辑

如果我不抛出另一个异常，我没有发生致命错误。对不起，我期望代码崩溃与我定义的错误消息，不是原始的异常messgae，所以：

Ok if I do not throw another exception I get no fatal error. Sorry I expected the code to crash with the error message I defined, not with the original exception messgae, so:

为什么不会失败与解析模型定义$ filePath 失败？

why doesnt it fail with "Parsing model definiion '$filePath' failed."?

编辑：

处理未捕获的异常的方法：

Turns out PHP has an iteresting way to deal with uncaught exceptions:

如果你抛出一个新的异常（MESSAGE，0，$ previous_exception），并且不抓住它将显示错误消息从$ previous_exception和NOTMESSAGE

If you throw an "new Exception("MESSAGE", 0,$previous_exception)" and do not catch it PHP will display the error message from $previous_exception and NOT "MESSAGE"

推荐答案

可能是因为你没有捕获异常，你会抛出catch块。

Probably because you don't catch the exception you throw in the catch block.

您必须停止在catch块中再次抛出异常，或者在调用方法中/ /在调用方法中新建一个try。

You have to either stop throwing exception again in the catch block, or make a new try catch around / in the calling method.

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