将数字转换为二进制 [英] Converting a number to binary

问题描述

这非常烦人，很久以前我需要将整数转换为二进制值以便上传到设备。工作得很好，不见了。可悲的是我现在需要将一个整数转换为二进制值。我真的需要这样做

This is very annoying, a long time ago I needed to convert an integer to a binary value for uploading to a device. Worked it out good and gone. The sad thing is I now need to convert an integer to a binary value for something else. I really need to get this going

String s = "05";
  int b = 0;

   StringBuilder binary = new StringBuilder();
   for (int j = 0; j <= binary.Length; j++ )
   {
       int val = b;
       for (int i = 0; i < 8; i++)
       {
           binary.Append((val & 128) == 0 ? 0 : 1);
           val <<= 1;
       }
       binary.Append(' ');
   }
 MessageBox.Show("'" + s + "' to binary: " + binary);

我希望5结束为101，将其添加到00000101我可以将零附加到字符串。

如果我运行代码它会锁定

from that I want 5 to end up as 101, to get it to 00000101 I can append the zeros to the string.
If I run the code it locks up

Quote：

Serial_Number.Form1。 button3_Click

（object sender = {Text =无法计算表达式，因为当前方法的代码已经过优化。}，

System.EventArgs e = {X = 46 Y = 6按钮=左}）第77行+ 0x40字节C＃

Serial_Number.Form1.button3_Click
(object sender = {Text = Cannot evaluate expression because the code of the current method is optimized.},
System.EventArgs e = {X = 46 Y = 6 Button = Left}) Line 77 + 0x40 bytes C#

并且调试器返回我做错了什么，我开始认为我需要更深入的路径通过我的系统代码。

格伦

and the debugger returns what am I doing wrong, I am starting to think I need a much deeper route through my system for the code.
Glenn

推荐答案

我不确定你想要外环做什么，但它看起来是无限的。



我已经评论了代码来解释原因：

I''m not sure what you intended the outer loop should do, but it appears to be infinite.

I''ve commented the code to explain why:

StringBuilder binary = new StringBuilder();
// Initial length of the StringBuilder is 0
// The loop will be entered as the condition is less than or equal to 0
for (int j = 0; j <= binary.Length; j++ )
  {
     int val = b;
     for (int i = 0; i < 8; i++)
       {
          binary.Append((val & 128) == 0 ? 0 : 1);
          val <<= 1;
       }
       binary.Append(' ');
       // StringBuilder Length has been increased by 9 characters
       // so the loop continuation condition is still true
  }

我一直使用System.Convert.ToString（Int32值，Int32 base）来获取''binary''字符串。它非常简单：

I''ve always used System.Convert.ToString(Int32 value, Int32 base) to get ''binary'' strings. It''s very straightforward:

// Assuming input is 8 bit
String s = Convert.ToString(5, 2);
// s = "101";
String result = s.PadLeft(8, '0');
// result = "00000101"

请停止它。一个数字已经是二进制的，除非它真的是一个数字，而不是一个数字的字符串表示。

这是非常基本的理解，你需要先学习基础知识。



是的，我明白你想要什么，一些字符串数据为001010101 ......。这是一个字符串！不要混用二进制，实际上就是......所有东西。

-SA

Please stop it. A number is already binary, unless it''s really a number, not a string representation of a number.
This is the very basic understanding, you need to learn basics first.

Yes, I understand what did you want, some string data as "001010101…". This is a string! Don''t mix is with binary, which is… everything, in fact.

—SA

如何（.NET 3.5，使用System.Linq; ）：

How about (.NET 3.5, using System.Linq;):

static string Bits(int v)
{
    return BitConverter
             .GetBytes(v)
             .Reverse()
             .Aggregate("", (s, b) => s + Convert.ToString(b, 2).PadLeft(8, '0'));
}
static string Bits(float v)
{
    return BitConverter
             .GetBytes(v)
             .Reverse()
             .Aggregate("", (s, b) => s + Convert.ToString(b, 2).PadLeft(8, '0'));
}
etc.

您可以使用Reverse（）来获取所需的字节顺序。

干杯

Andi

You may play with the Reverse() to get the byte order you want.
Cheers
Andi

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