使用每个二进制数将二进制数转换为数组 [英] Convert a binary to an array with each binary number

问题描述

我试图将每个1/0的二进制值转换为列表，但是我得到默认的二进制值而不是列表.

I am trying to convert a binary value to a list with each 1/0 but I get the default binary value and not the list.

我有一个字符串，我将每个字符转换为二进制，它为我提供了一个列表，其中包含每个字符的字符串.现在，我试图将每个字符串拆分为值0/1的整数，但我什么也没得到.

I have a string, I convert each character in binary and it gives me an list with a string for each character. Now I am trying to split each string into ints with the value 0/1 but I can't get anything.

# if message = "CC"
message="CC"

# just a debug thing
for c in message:
    asci = ord(c)
    bin = int("{0:b}".format(asci))
    print >> sys.stderr, "For %c, asci is %d and bin is %d" %(c,asci,bin)

c = ["{0:b}".format(ord(c)) for c in message]
# c = ['1000011', '1000011']
bin = [int(c) for c in c]
#bin should be [1,0,0,0,0,1,1,1,0,0,0,0,1,1]
# but I get [1000011, 1000011]
print >> sys.stderr, bin

推荐答案

如果您有此内容:

c = ['1000011', '1000011']

您要实现这一目标:

[1,0,0,0,0,1,1,1,0,0,0,0,1,1]

您可以这样做:

modified_list=[int(i) for  element in c for i in element]

或者您可以使用itertools.chain

from itertools import chain
modified_list=list(chain(*c)) 

当您想同时加入列表理解功能时，可以通过以下方式做到这一点:

As you want to join both the list comprehension, you can do it this way:

bin= list( chain( *["{0:b}".format(ord(c)) for c in message] )

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