二进制数? [英] binary numbers?
问题描述
我使用Python外壳弄清楚如何在Python打印命令的作品。结果
当我键入
打印01结果
1结果
打印010结果
8结果
打印0100结果
64结果
打印030结果
24
块引用>
块引用>
块引用>这是怎么回事?难道仅仅是基础2?为什么一在第二位置打印8?难道不应该是2,如果是二进制?
解决方案启动一批以零标记为在Python 2进制这已经被认为是混乱的,令人惊讶的也不一致,如以0x开始将迎来它为十六进制。因此,在Python 3,从0开始是无效的,你用0°开始得到八进制。您也可以开始使用0B将其标记为二进制文件。
>>> 10
10
>>>为0x10
16
>>> 0o10
8
>>> 0b10
2
>>> 010
文件<&标准输入GT;,1号线
010
^
语法错误:无效令牌0X,0°和0B也适用在Python 2.6和Python 2.7。
I am using the python shell to figure out how the print command works in python.
When I type inprint 01
1
print 010
8
print 0100
64
print 030
24
What's going on here? Is it just base 2? Why does the "one" in the second position print as 8? Shouldn't it be 2 if it's binary?
解决方案Starting a number with a zero marks it as octal in Python 2. This has been recognized as confusing, surprising and also inconsistent, as starting with 0x will mark it as hexadecimal. Therefore, in Python 3, starting with 0 is invalid, and you get octal by starting with 0o. You can also start with 0b to mark it as binary.
>>> 10 10 >>> 0x10 16 >>> 0o10 8 >>> 0b10 2 >>> 010 File "<stdin>", line 1 010 ^ SyntaxError: invalid token
0x, 0o and 0b also works in Python 2.6 and Python 2.7.
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