用C添加二进制数++ [英] Adding binary numbers in C++

问题描述

我怎么会加入C ++两个二进制数？什么是正确的逻辑？

下面是我的努力，但它似乎并不正确：

 的#include＆LT;＆iostream的GT;
使用命名空间std;
诠释的main（）
{
    诠释一个[3];
    INT B〔3〕;
    INT携带= 0;
    INT结果[7];    一个[0] = 1;
    一个[1] = 0;
    一个[2] = 0;
    一个[3] = 1;    B [0] = 1;
    B〔1] = 1;
    B〔2] = 1;
    B〔3〕= 1;    的for（int i = 0; I＆LT; = 3;我++）
    {
        如果（A [I] + B [I] +携带== 0）
        {
            结果由[i] = 0;
            携带= 0;
        }        如果（A [I] + B [I] +携带== 1）
        {
            结果由[i] = 0;
            携带= 0;
        }        如果（A [I] + B [I] +携带== 2）
        {
            结果由[i] = 0;
            携带= 1;
        }        如果（一个由[i] + B [I] +携带→2）
        {
            结果由[i] = 1;
            携带= 1;
        }
    }
    对于（INT J = 0; J＆LT; = 7; J ++）
    {
        COUT＆LT;＆LT;结果[J]＆LT;＆LT;;
    }
    系统（暂停）;
}
 

解决方案

嗯，这是一个pretty琐碎的问题。

  

的如何在C添加两个二进制数++。什么是它的逻辑。的

有关增加两个二进制数，a和b。你可以用下面的公式来做到这一点。

  

和=一个XOR B

  
  

随身= AB

这是一个半加器方程。

现在要实现这一点，你可能需要了解全加器原理的作品。

  

和=一个XOR B XORç

  
  

随身= AB + BC + CA

由于您存储二进制数的int数组，你可能想了解位运算。
您可以使用^异或，|运营商OR，＆安培;运营商和

下面是一个简单的code来计算的总和。

 为（i = 0; I＆LT; 8;我++）{
   总和[I] =（（A [I] ^ B [I]）^ C）; // c是携带
   C =（（一个由[i]和b [I]）|（一个由[i]和C））| （二[I]和C）;
}
 

How would I add two binary numbers in C++? What is the correct logic?

Here is my effort, but it doesn't seem to be correct:

#include <iostream>
using namespace std;
int main()
{
    int a[3];
    int b[3];
    int carry = 0;
    int result[7];

    a[0] = 1;
    a[1] = 0;
    a[2] = 0;
    a[3] = 1;

    b[0] = 1;
    b[1] = 1;
    b[2] = 1;
    b[3] = 1;

    for(int i = 0; i <= 3; i++)
    {
        if(a[i] + b[i] + carry == 0)
        {
            result[i] = 0;
            carry = 0;
        }

        if(a[i] + b[i] + carry == 1)
        {
            result[i] = 0;
            carry = 0;
        }

        if(a[i] + b[i] + carry == 2)
        {
            result[i] = 0;
            carry = 1;
        }

        if(a[i] + b[i] + carry > 2)
        {
            result[i] = 1;
            carry = 1;
        }
    }
    for(int j = 0; j <= 7; j++)
    {
        cout<<result[j]<<" ";
    }
    system("pause");
}

解决方案

Well, it is a pretty trivial problem.

How to add two binary numbers in c++. what is the logic of it.

For adding two binary numbers, a and b. You can use the following equations to do so.

sum = a xor b

carry = ab

This is the equation for a Half Adder.

Now to implement this, you may need to understand how a Full Adder works.

sum = a xor b xor c

carry = ab+bc+ca

Since you store your binary numbers in int array, you might want to understand bitwise operation. You can use ^ for XOR,| operator for OR, & operator for AND.

Here is a sample code to calculate the sum.

for(i = 0; i < 8 ; i++){
   sum[i] = ((a[i] ^ b[i]) ^ c); // c is carry
   c = ((a[i] & b[i]) | (a[i] & c)) | (b[i] & c); 
}

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