十进制二进制用C [英] Decimal to Binary in C

问题描述

我要创建一个程序，加减2个数字。然后，我要输出这个答案分成不同的基地。

I'm creating a program that adds and subtracts 2 numbers. Then I have to output this answer into different bases.

我的回答是十进制格式，为long double类型，如：

My answer is in decimal format, of type long double, such as:

long double answer;
answer = numberOne + numberTwo;

我想这个答案转换成二进制。现在，我刚才在我的计划，这是否使用code，但有一个字符指针：

I want to convert this answer into binary. Now I have code used earlier in my program that does this, but with a char pointer:

char * decimalBinary (char * decimalNumber) 
{

    bool zeroFront = true;
    int i;
    int z;
    int j = 0;
    int n = atoi(decimalNumber);
    char * binaryNum = malloc(32+1);
    binaryNum[32] = '\0';

    int current_index=1;
    int end_index = strlen(decimalNumber)-1;

    //Error check for valid decimal input, needed error check for beginning of code
    while(current_index <= end_index)
    {
        if(decimalNumber[current_index] != '0' &&decimalNumber[current_index] != '1' &&decimalNumber[current_index] != '2' &&decimalNumber[current_index] != '3' &&decimalNumber[current_index] != '4' &&decimalNumber[current_index] != '5' &&dec[current_index] != '6' &&dec[current_index] != '7' &&decimalNumber[current_index] != '8' &&decimalNumber[current_index] != '9')
        {
            binaryNum[0] = -8;
            return binaryNum;
        }
        current_index++;
    }


    for (i = 31; i >= 0; i--) {
        z = n >> i;

        if (z & 1) 
        {
            binaryNum[j] = '1';
            j++;
            zeroFront = false;
        } 
       else if (!zeroFront) 
       {
            binaryNum[j] = '0';
            j++;
        }
    }

    binaryNum[j] = '\0';

    return binaryNum;
}

我的preferred解决方案是使用code我已经在我的计划，我的回答转换成二进制格式，但你可以看到参数是相互矛盾的，我不知道如何去这样做。

My preferred solution is to use the code I already have in my program to convert my answer into a binary format, but as you can see the parameters are conflicting, and I'm not sure how to go about doing that.

这是从我的程序具有可重用code减损另一种可能的解决方案是创建一个不同的功能一起，一个十进制数转换为二进制，但接受long类型double的参数，这是一个有点不清楚我也是。

Another possible solution that detracts from having reusable code in my program, is to create a different function all together that converts a decimal to a binary, but accepting a parameter of type long double, which is a bit unclear to me as well.

编辑：
取而代之的长双，我的答案是类型 INT 。

Instead of long double, my answer is of type int.

推荐答案

如果你真的想重用你的功能，无需修改，您可以将答案成十进制字符串和该字符串传递给你的函数。

If you really want to reuse your function without modifications, you can transform answer into a decimal string and pass the string to your function.

char stringAnswer[20];
sprintf(stringAnswer, "%d", answer);
printf("the binary answer is %s\n", decimalBinary(stringAnswer));

但是，一个更好的解决方案应该是功能 decimalBinary 分裂成两个功能：第一个检查所有的数字都OK，而第二个转换一个 INT 成二进制字符串。
然后，你就可以直接调用与答案第二个函数的参数。

But a better solution should be to split the function decimalBinary into two functions : the first one to check that all digits are ok, and the second one to convert a int into a binary string. Then you'll be able to call directly this second function with answer as parameter.

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