在MATLAB中从二进制数转换为十进制数 [英] Conversion from binary to decimal number in MATLAB

问题描述

我无法将二进制转换为十进制(似乎很长).

I have a problem in converting the binary to decimal (it seems very lengthy).

%% Read

clear all;
close all;
clc;
I=imread('test.png');
imshow(I);

%% Crop
I2 = imcrop(I);
figure, imshow(I2)
w=size(I2,1);
h=size(I2,2);
%% LBP
for i=2:w-1
    for j=2:h-1
        J0=I2(i,j);
        I3(i-1,j-1)=I2(i-1,j-1)>J0;
        I3(i-1,j)=I2(i-1,j)>J0;
        I3(i-1,j+1)=I2(i-1,j+1)>J0; 
        I3(i,j+1)=I2(i,j+1)>J0;
        I3(i+1,j+1)=I2(i+1,j+1)>J0; 
        I3(i+1,j)=I2(i+1,j)>J0; 
        I3(i+1,j-1)=I2(i+1,j-1)>J0; 
        I3(i,j-1)=I2(i,j-1)>J0;
        LBP(i,j)=I3(i-1,j-1)*2^8+I3(i-1,j)*2^7+I3(i-1,j+1)*2^6+I3(i,j+1)*2^5+I3(i+1,j+1)*2^4+I3(i+1,j)*2^3+I3(i+1,j-1)*2^2+I3(i,j-1)*2^1;
    end
end
figure,imshow(I3)
figure,imhist(LBP)

是否可以更改此行

LBP(i,j)=I3(i-1,j-1)*2^8+I3(i-1,j)*2^7+I3(i-1,j+1)*2^6+I3(i,j+1)*2^5+I3(i+1,j+1)*2^4+I3(i+1,j)*2^3+I3(i+1,j-1)*2^2+I3(i,j-1)*2^1;

要短些吗?

推荐答案

选项1:

一种简化操作的方法是，首先创建一个3×3比例因子矩阵(即2的幂)，然后在循环之前将其初始化:

Option 1:

One way to simplify what you're doing is to first create a 3-by-3 matrix of scale factors (i.e. powers of two) and initialize it before your loops:

scale = 2.^[8 7 6; 1 -inf 5; 2 3 4];

然后，您可以使用以下矢量化操作替换循环中的所有内容:

Then you can replace everything inside your loop with these vectorized operations:

temp = (I2(i-1:i+1,j-1:j+1) > I2(i,j)).*scale;
LBP(i,j) = sum(temp(:));

选项2:

或者，我相信您可以完全删除两个循环，并用对 NLFILTER 获取矩阵LBP:

LBP = nlfilter(I2,[3 3],@(x) sum((x(:) > x(5)).*scale(:)));

这篇关于在MATLAB中从二进制数转换为十进制数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！