将9.2532十进制转换为二进制MATLAB [英] convert 9.2532 decimal into binary matlab
问题描述
我使用de2bi(x),但是它仅对整数有效,我想将点十进制的数字转换为二进制
I use de2bi(x) but it help only for integer i want to convert for digit with point decimal into binary
de2bi(x)
将此9.2553转换为带有小数部分的十进制,如果没有可能的话,也可以在Matlab中将其转换成二进制格式,而不是将要输出代码的函数文件
convert this 9.2553 into decimal with fraction part also convert into binary format in Matlab if possible than without function file with code want output
推荐答案
MATLAB, of course, already stores double values in binary using IEEE-754 binary64 format. All we have to do is somehow get MATLAB to show us the bits.
一种方法是使用 typecast ,这会使MATLAB解释一个一组不同类型的内存位置.在这种情况下,我们将使MATLAB认为double
是uint64
,然后通过dec2bin
发送整数".之后,我们必须对字符串进行一些分解才能获得实际值.
One way is to use typecast which makes MATLAB interpret a set of memory locations as a different type. In this case, we'll make MATLAB think a double
is a uint64
and then send the "integer" through dec2bin
. We'll have to do some decomposition on the string after that to get the actual value.
注意:当前仅适用于正值.如果您还需要负值,我将不得不进行一些调整.
Note: This currently only works with positive values. If you need negative values too, I'll have to make some adjustments.
function binstr = double2bin(d)
d = double(d); % make sure the input is a double-precision float
ieee754_d = dec2bin(typecast(d, 'uint64'),64); % read double as uint64
% IEEE-754 64-bit double:
% bit 1 (msb) = sign bit (we'll ignore this for now)
% bits 2-12 = exponent with bias of 1023
% bits 13-64 = significand with leading 1 removed (implicit)
exponent = bin2dec(ieee754_d(2:12))-1022; % 2^n has n+1 bits
significand = ['1' ieee754_d(13:64)];
if (exponent < 1) % d < 1, so we'll need to pad with zeros
binstr = ['0.' repmat('0',1,-exponent) significand];
else % d >= 1; move exponent bits to the left of binary point
binstr = [significand(1:exponent) '.' significand(exponent+1:end)];
end
end
试运行:
>> double2bin(9.2532)
ans = 1001.0100000011010001101101110001011101011000111000100
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