Python将二进制转换为十进制 [英] Python-Converting binary to decimal

问题描述

我正在执行冲突分配，这使我们创建了一个python程序，无需使用bin()函数或list()即可将二进制转换为十进制.我计划将每个1和0存储在一个函数中，该函数将在以后相乘.但是，我不确定应该怎么做

Im doing a colledge assignment which is have us create a python program to convert binary to decimal without using the bin() function or list(). I'm plan to have each 1's and 0's stored in a function which will be multiplied later. However, I'm not sure how am i suppose to do so

推荐答案

好吧，您可以将二进制数字作为字符串传递，并以相反的顺序对其进行迭代，将每个0或1乘以2 ^ n，其中n为每个循环周期递增一个数字.

Well, you could pass the binary number as a string, and iterate over it in reverse order, multiplying each 0 or 1 by 2^n, where n is a number incremented at each loop cycle.

def bin2dec(b):
    number = 0
    counter = 0
    for i in b[::-1]: # Iterating through b in reverse order
        number += int(i)*(2**counter)
        counter += 1

    return number

bin2dec("101010") # 42

就像Byte Commander一样，您也可以在循环中使用枚举而不是手动计数器，它具有相同的目的.

EDIT : Like Byte Commander did, you could also use enumerate in the loop instead of a manuel counter, it serve the same purpose.

def bin2dec(b):
    number = 0
    for idx, num in enumerate(b[::-1]): # Iterating through b in reverse order
        number += int(num)*(2**idx)

    return number

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