转换二进制数组转换为十进制 [英] Convert binary to decimal with an array

问题描述

我试着做一个二进制字符串为十进制。如果输入-1它将终止。我坚持使用数组。有人建议使用方法：公共静态INT binaryToDecimal（字符串binaryString）。但林不知道该怎么做。这是我有：

Im trying to make a binary string into a decimal. It will terminate if -1 is entered. I am stuck with using an array. It was suggested to use: public static int binaryToDecimal (String binaryString) . But Im not sure how to do that. This is what I have:

import java.util.Scanner;

public class BinaryConversion {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

        String inString;
        int decimal;

        System.out.println("Enter a binary number: ");
        inString = input.nextLine();

        while (inString != "-1") {
            int i;
            int binaryLength;

            binaryLength = inString.length();

            for (i = 0, decimal = 0; i < binaryLength; i++) {
                decimal = decimal * 2 + (inString[i] - 0);
                System.out.print(decimal);

            } 
            System.out.println("Enter a binary number: ");
            inString = input.nextLine();
        }
        System.out.println("All set !");
    }
}

它说，有与阵列汇编问题。谢谢！

It says there is a compilation problem with the array. Thank you!

推荐答案

您可以通过使用简化code 的Integer.parseInt（）：

You can simplify the code by using Integer.parseInt():

public static void main(String[] args) {
    final Scanner input = new Scanner(System.in);

    String inString;

    while (true) {
        System.out.println("Enter a binary number: ");
        inString = input.nextLine();

        if (inString.equals("-1"))
            break;

        System.out.println(Integer.parseInt(inString, 2));
    }
    System.out.println("All set !");
}

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