在Matlab中将十进制转换为二进制？ [英] Convert decimal to binary in Matlab?

问题描述

我将基数为10的数字转换为基数为2的数字，并指定我想用来表示这些基数为10的数字的位数。

这里是我的负数的代码：

  function output = DTB（decimal，binary）
 if decimal< 0 
 smallestNum =  - （2 ^（bits-1））; 
 
如果十进制< smallestNum 
错误（'％d不能用％d位表示，增加位数。'，decimal，bits）; 
 output =''; 
 end 
 
 output ='1'; 
位=位 -  1; 
 
 if smallestNum ==十进制
 while bits〜= 0 
 output = [output，'0']; 
位=位 -  1; 
 end 
 end 
 
 num = smallestNum; 
 while num〜= decimal 
 num = smallestNum + 2 ^（bits-1）; 
 if num>十进制
 output = [output，'0']; 
 else 
 output = [output，'1']; 
 smallestNum = smallestNum + 2 ^（bits-1）; 
 end 
 bits = bits  -  1; 
 end 
 
 while bits〜= 0 
 output = [output，'0']; 
位=位 -  1; 
 end 
 end 
  

这很好。我遇到的问题（奇怪的是，因为从正数到二进制应该更容易）是正整数。它应该是对负数算法的一个小调整，对吧？例如，正数字段在小数 = 8和位 = 6的情况下不起作用不适用于2的不同权力）。这是什么错误，在这里？

以下是正整数的代码：

 如果小数点> 0 
 largestNum =（2 ^（bits-1）） -  1; 
 
如果小数点> maximumNum 
错误（'％d不能用％d位表示。增加位数。'，decimal，bits）; 
 output =''; 
 end 
 
％第一个点必须为零才能显示它是正数
 output ='0'; 
位=位 -  1; 
 
 largestNum = largestNum + 1; 
 num = largestNum; 
 
 while num〜= decimal 
 num = largestNum  -  2 ^（bits-1）; 
 if num>十进制
 output = [output，'0']; 
结束
如果num <=十进制
 output = [output，'1']; 
 largestNum = largestNum  -  2 ^（bits-1）; 
 end 
 bits = bits  -  1; 
 end 
 
 while bits〜= 0 
 output = [output，'0']; 
位=位 -  1; 
 end 
  

解决方案

当你在输出数组中放置一个零时，因为你本质上是从一个二进制数组开始的（即最大数）。这段代码适用于我：

  if decimal> 0 
 largestNum =（2 ^（bits-1）） -  1; 
 
如果小数点> maximumNum 
错误（'％d不能用％d位表示。增加位数。'，decimal，bits）; 
 output =''; 
 end 
 
第一个点必须为零才能显示它是一个正数
 output ='0'; 
位=位 -  1; 
 
 largestNum = largestNum + 1; 
 num = largestNum; 
 
 while num〜= decimal 
 num = largestNum  -  2 ^（bits-1）; 
 if num>十进制
 output = [output，'0']; 
 largestNum = largestNum  -  2 ^（bits-1）; 
结束
如果num <=十进制
 output = [output，'1']; 
 
 end 
 bits = bits  -  1; 
 end 
 
 while bits〜= 0 
 output = [output，'0']; 
位=位 -  1; 
 end 
 end 
  

我不确定这是为了什么，但我强烈建议使用内置的 dec2bin 来执行此操作。

I am converting base-10 numbers to base-2 numbers, and specifying the number of bits I'd like to use to represent these base-10 numbers.

Here's my code for negative numbers:

function output = DTB(decimal,binary)
if decimal < 0
    smallestNum = -(2^(bits-1));

    if decimal < smallestNum
        error('%d cannot be represented in %d bits. Increase the number of bits. ',decimal,bits);
        output = '';
    end

    output = '1';
    bits = bits - 1;

    if smallestNum == decimal
        while bits ~= 0
            output = [output,'0'];
            bits = bits - 1;
        end
    end

    num = smallestNum;
    while num ~= decimal
        num = smallestNum + 2^(bits-1);
        if num > decimal
            output = [output,'0'];
        else
            output = [output,'1'];
            smallestNum = smallestNum + 2^(bits-1);
        end
        bits = bits - 1;
    end

    while bits ~= 0
        output = [output,'0'];
        bits = bits - 1;
    end
end

This works fine. The issue I'm running into (oddly enough, since going from positive decimals to binary should be easier) is with positive integers. It should just be a minor tweak to the negative number algorithm, right? The positive number piece does not work in the case of decimal = 8 and bits = 6, for example (it doesn't work for different powers of 2). What's wrong, here?

Here's the code for positive integers:

if decimal > 0
    largestNum = (2^(bits-1))-1;

    if decimal > largestNum
        error('%d cannot be represented in %d bits. Increase the number of bits. ',decimal,bits);
        output = '';
    end

    % first spot must be zero to show it's a positive number
    output = '0';
    bits = bits - 1;

    largestNum = largestNum + 1;
    num = largestNum;

    while num ~= decimal
        num = largestNum - 2^(bits-1);
        if num > decimal
            output = [output,'0'];
        end
        if num <= decimal
            output = [output,'1'];
            largestNum = largestNum - 2^(bits-1);
        end
        bits = bits - 1;
    end

    while bits ~= 0
        output = [output,'0'];
        bits = bits - 1;
    end

解决方案

You need to reduce largest num when you put a zero in the output array, because you're essentially starting from a binary array of all ones (ie largestNum). This code worked for me:

if decimal > 0
largestNum = (2^(bits-1))-1;

if decimal > largestNum
    error('%d cannot be represented in %d bits. Increase the number of bits. ',decimal,bits);
    output = '';
end

% first spot must be zero to show it\'s a positive number
output = '0';
bits = bits - 1;

largestNum = largestNum + 1;
num = largestNum;

while num ~= decimal
    num = largestNum - 2^(bits-1);
    if num > decimal
        output = [output,'0'];
        largestNum = largestNum - 2^(bits-1);
    end
    if num <= decimal
        output = [output,'1'];

    end
    bits = bits - 1;
end

while bits ~= 0
    output = [output,'0'];
    bits = bits - 1;
end
end

I'm not sure what this is for, but I would highly recommend using the built in dec2bin to do this.

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