在'EXE'项目中设置'启动命令参数' [英] Setting 'startup command arguments' in 'EXE' project

问题描述

 

我们需要通过启动Visual Studio 2015并将exe作为项目打开来实现自动化：

we need to automation Visual Studio 2015 by launching it and opening an exe as project:

dte .ExecuteCommand（" File.OpenProject"，@" MyExecutable.exe"）;

dte.ExecuteCommand("File.OpenProject", @"MyExecutable.exe");

但是我们还需要添加一些启动参数，这似乎有些问题，因为project似乎不是VCproject，也不是.NET项目（动态转换不起作用）。有没有人知道如何输入启动参数？

However we also need to add some startup arguments and this seems to be somewhat of an issue since the project doesn't appear to be a VCproject, nor a .NET project (dynamic casting doesn't work). Does anyone have an idea on how to enter the startup arguments?

提前致谢。

问候。

Yves

推荐答案

Hi Puelings，

Hi Puelings,

我们可以使用System.Diagnostics.Process方法有了实现它的论据。像这样：

We could use System.Diagnostics.Process method with arguments to achieve it. like this:

ProcessStartInfo startInfo = new ProcessStartInfo("MyExecutable.exe");
startInfo.WindowStyle = ProcessWindowStyle.Normal;

// Start with one argument.
// Output of ArgsEcho:
//  [0]=/a            
startInfo.Arguments = "/a";
System.Diagnostics.Process.Start(startInfo);

有关详细信息，请参阅：

For more information, please refer to:

HTTPS：// MSDN。 microsoft.com/en-us/library/system.diagnostics.processstartinfo.arguments(v=vs.110).aspx?cs-save-lang=1&cs-lang=csharp#code-snippet-1

祝你好运，

Cole Wu

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