比较两个数组的所有元素后，如何获取值？ [英] How can I get a value after compare all the elements of two arrays?

问题描述

我想比较两个数组的元素，这是我的代码：

  public  < span class =code-keyword> class  twoarrs {
 
  boolean  arrays（ int  [] arr1， int  [] arr2）{
  //   arr1 = new int [2];  
  //   arr2 = new int [arr1.length];  
 
  for （ int  i =  0 ; i< = arr1.length  -   1 ; i ++）{ 
  for （ int  j =  0 ; j< = arr2.length  -   1 ; j ++）{
  if （ arr1 [i]< arr2 [j]）{ 
 System.out.println（ 这是真的）; 
} 
  else  {
 System.out.println（ 这是假）; 
} 
} 
} 
 返回 true; 
 
} 
 
  public   static   void  main（ String  [] args）{
 twoarrs compare =  new  twoarrs（）; 
  int  [] a1 = { 4 ， 5 }; 
  int  [] a2 = { 1 ， 200 }; 
 compare.arrays（a1，a2）; 
} 
} 

此代码将在屏幕上打印四个结果（现在它们是假的，真的，false，true），如果a1中的所有元素都小于a2中的元素，我该如何返回真值？意味着我想在执行所有for循环后返回一个值。



如果我添加隐藏的代码，为什么结果都是假的？



任何帮助？谢谢。

解决方案

如果我已正确理解你的问题

你可以试试这个方法

< pre lang =java> boolean arrays（ int [] arr1， int [] arr2）
{
for （ int i = 0 ; i< = arr1.length - 1 ; i ++）
for （ int j = 0 ; j < = arr2.length - 1 ; j ++）
if （arr1 [i]> ; arr2 [j]）
return false;
返回 true;
}

关于你的上一个问题，如果你的意思是注释代码而不是隐藏代码，答案就是

构造数组时默认值为0所以

arr1 = {0,0}

arr2 = {0,0}

所以结果是假的

  private   boolean 数组（ int  [] arr1， int  [] arr2）{
  boolean  bReturn = false;  //  返回值的预张贴 
  for （ int  i =  0 ; i< = arr1.length  -   1 ; i ++）{
  for （ int  j =  0 ; j< = arr2.length  -   1 ; j ++）{
  if （arr1 [i]> arr2 [j]）{
 bReturn = true;  //  如果arr1的值高于arr2，则返回值 
} 
} 
} 
  return  bReturn;  //  已完成。返回结果。如果truearr1的值至少高于arr2的最低值。 
} 

I want to compare the element of two arrays, here is my code:

public class twoarrs {

		boolean arrays(int[] arr1, int[] arr2){
//			arr1 = new int[2];
//			arr2 = new int[arr1.length];
						
			for (int i = 0; i <= arr1.length - 1; i++){
				for (int j = 0; j <= arr2.length - 1; j++){
					if (arr1[i] < arr2[j]){
						System.out.println("this is true");
					}
					else{
						System.out.println("this is false");	
					}						
				}
			}
                        return true;

		}
		
		public static void main(String[] args){
			twoarrs compare = new twoarrs();
			int[] a1 = {4,5};
			int[] a2 = {1,200};
			compare.arrays(a1, a2);
		}
}

This code will print four results on the screen(for now they are false, true, false, true), how can I return a true value if all the elements in a1 are smaller than the elements in a2? Means I want to return a value after all the for loops are executed.

And why the result will be all false if I add the code which were hidden?

Any help? Thank you.

解决方案

If I have understood your question correctly
You can Try this Method instead

boolean arrays(int[] arr1, int[] arr2)
{
       for (int i = 0; i <= arr1.length - 1; i++)
	   for (int j = 0; j <= arr2.length - 1; j++)
		if (arr1[i] > arr2[j])
		    return false;								
       return true;
}

About your last question, If you meant commented code instead of hidden code the answer is that
when arrays are constructed the default value is 0 so
arr1 = {0,0}
arr2 = {0,0}
so the results are false

private boolean arrays(int[] arr1, int[] arr2){
  boolean bReturn = false; // pretension for return value
  for (int i = 0; i <= arr1.length - 1; i++) {
    for (int j = 0; j <= arr2.length - 1; j++) {
      if (arr1[i] > arr2[j]){
        bReturn = true; // if it happens that arr1 has a higher value than arr2, the return value is changed
      }		
    }
  }
  return bReturn; // done. return result. if "true" arr1 has at least one higher value than the lowest value of arr2.
}

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