如何删除基类指针? [英] How to delete the Base class pointer?
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问题描述
这是我的完整代码.......
This is mine whole code.......
class Interface
{
public:
virtual void fun()=0;
};
class Derived:public Interface
{
public:
void fun()
{
printf("i am in derived class fun\n");
}
};
int main()
{
Interface *pInterface;
Derived obj_Derived;
pInterface=&obj_Derived;
pInterface->fun();
return 0;
}
我想删除
I want to delete the
pInterface pointer
,因此我可以调用
delete pInterface;
否则我应该在Interface类中使用虚拟析构函数.
or should i have to take virtual destructor in Interface class.
推荐答案
虚拟析构函数将是一个好主意,但您的主要示例不需要任何删除!,因为在堆栈上实例化了obj_Derived.
将示例更改为
时
Virtual destructor would be a good idea, BUT your main example does NOT need any delete!, cause obj_Derived is instanciated on stack.
When changing the example to
int main()
{
Interface *pInterface;
pInterface=new Derived();
pInterface->fun();
delete pInterface;
return 0;
}
然后,虚拟析构函数将完成这项工作.
THEN the virtual destructor will do the job.
您猜对了:
You guessed correctly:
delete pInterface;
将不会执行此操作,因为编译器不知道该对象将要删除哪个对象.因此,在您的接口类中声明一个虚拟析构函数,一切都会好起来.
will not do the job, because the compiler has no idea about which object is going to be deleted by this. So declare a virtual destructor in your interface class and all will be fine.
//我想删除 pInterface /> 为什么 ?没有新了...:)
// I want to delete the pInterface
Why ? There was no new for it... :)
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