将uString转换为Const char * [英] Converting uString to Const char *

问题描述

伙计们，

我想问一些有关转换变量的问题.
故事发生在我拥有时:

Hola guys,

I wanna ask something about converting variable.
The story goes when I have :

uString text;

我需要他将其转换为const char *.
我已经尝试过将std :: string转换为const char的方法，但是没有用.

which I need he to be convert as const char *.
I''ve tried the same way how to convert std::string to const char, but it didn''t work.

std::string str;
char * writable = new char[str.size() + 1];
std::copy(str.begin(), str.end(), writable);
writable[str.size()] = '\0'; 

delete[] writable;
                        // NOOTTTT WORRRKKKK FOR MEE!!!!//////

有人知道怎么做吗?

谢谢

Anybody knows how to do it?

Thanks

推荐答案

我不确定，但这听起来像您有一个将const char *作为输入的函数，而您所拥有的只是一个std :: string.如果是这种情况，您现在可以忘记const部分-在那里可以向您指示，并且可以由编译器强制执行，该函数在执行过程中不会对该变量进行任何更改. -这将积极防止将数据写入引用的var.

但是，回到眼前的问题，如何将std :: string转换为更有用的东西.

普通的简单1衬里怎么样?

I can''t be sure, but it sounds like you have a function that takes a const char* as an input, and all you have is a std::string. If that''s the case, you can forget about the const part for now - that''s there to indicate to you and be made enforceable by the compiler that no changes will happen to that variable during the function. - This will actively prevent writing data to a var that''s a reference.

But, getting back to the issue at hand, how to convert a std::string into something more useful.

How about just this plain and simple 1 liner?

char *writeable = str.c_str();

您可以在此处找到文档: http://www.cplusplus.com/reference/string/string/c_str/ [ ^ ]

请特别注意，您(a)不必自己分配内存(b)您不必自己释放内存(c)您不应尝试对其进行修改-它是const char *

You can find the docs here: http://www.cplusplus.com/reference/string/string/c_str/[^]

Note specifically, you (a) don''t have to allocate the memory yourself (b) you don''t have to free it yourself (c) you shouldn''t try to modify it - it''s a const char*

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