将const char *转换为const wchar_t * [英] Convert const char* to const wchar_t*

问题描述

我试图创建一个程序与Irrlicht加载某些东西从一个配置文件中写的Lua，其中之一是窗口标题。然而， lua_tostring 函数返回一个 const char * ，而Irrlicht设备的方法 setWindowCaption 期望一个 const wchar_t * 。如何转换 lua_tostring ？返回的字符串

I am trying to create a program with Irrlicht that loads certain things from a configuration file written in Lua, one of which is the window title. However, the lua_tostring function returns a const char* while the Irrlicht device's method setWindowCaption expects a const wchar_t*. How can I convert the string returned by lua_tostring?

推荐答案

多个问题，以解决Windows上的问题。示例信息：

There are multiple questions on SO that address the problem on Windows. Sample posts:

1. char * to const wchar_t * conversion


2. 从unsigned char *转换为const wchar_t *

1. char* to const wchar_t * conversion
2. conversion from unsigned char* to const wchar_t*

平台无关方法发布在 http://ubuntuforums.org/showthread.php?t=1579640。此网站的来源（我希望我没有违反任何版权）：

There is a platform agnostic method posted at http://ubuntuforums.org/showthread.php?t=1579640. The source from this site is (I hope I am not violating any copyright):

#include <locale>
#include <iostream>
#include <string>
#include <sstream>
using namespace std ;

wstring widen( const string& str )
{
    wostringstream wstm ;
    const ctype<wchar_t>& ctfacet = 
                        use_facet< ctype<wchar_t> >( wstm.getloc() ) ;
    for( size_t i=0 ; i<str.size() ; ++i ) 
              wstm << ctfacet.widen( str[i] ) ;
    return wstm.str() ;
}

string narrow( const wstring& str )
{
    ostringstream stm ;
    const ctype<char>& ctfacet = 
                         use_facet< ctype<char> >( stm.getloc() ) ;
    for( size_t i=0 ; i<str.size() ; ++i ) 
                  stm << ctfacet.narrow( str[i], 0 ) ;
    return stm.str() ;
}

int main()
{
  {
    const char* cstr = "abcdefghijkl" ;
    const wchar_t* wcstr = widen(cstr).c_str() ;
    wcout << wcstr << L'\n' ;
  }
  {  
    const wchar_t* wcstr = L"mnopqrstuvwx" ;
    const char* cstr = narrow(wcstr).c_str() ;
    cout << cstr << '\n' ;
  } 
}

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