我想将 std::string 转换为 const wchar_t * [英] I want to convert std::string into a const wchar_t *

问题描述

有什么方法吗?我的电脑是AMD64.

Is there any method? My computer is AMD64.

::std::string str;
BOOL loadU(const wchar_t* lpszPathName, int flag = 0);

当我使用:

loadU(&str);

VS2005 编译器说:

the VS2005 compiler says:

Error 7 error C2664:: cannot convert parameter 1 from 'std::string *__w64 ' to 'const wchar_t *'

我该怎么做?

推荐答案

如果你有一个 std::wstring 对象，你可以在它上面调用 c_str() 来得到一个 wchar_t*:

If you have a std::wstring object, you can call c_str() on it to get a wchar_t*:

std::wstring name( L"Steve Nash" );
const wchar_t* szName = name.c_str();

然而，由于您在一个狭窄的字符串上操作，您首先需要将其加宽.这里有多种选择；一种是使用Windows内置的MultiByteToWideChar 例程.这会给你一个 LPWSTR，它等价于 wchar_t*.

Since you are operating on a narrow string, however, you would first need to widen it. There are various options here; one is to use Windows' built-in MultiByteToWideChar routine. That will give you an LPWSTR, which is equivalent to wchar_t*.

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