如何将 char* 转换为 wchar_t*? [英] How to convert char* to wchar_t*?

问题描述

我尝试过实现这样的功能，但不幸的是它不起作用:

I've tried implementing a function like this, but unfortunately it doesn't work:

const wchar_t *GetWC(const char *c)
{
    const size_t cSize = strlen(c)+1;
    wchar_t wc[cSize];
    mbstowcs (wc, c, cSize);

    return wc;
}

我的主要目标是能够在 Unicode 应用程序中集成普通字符字符串.非常感谢你们提供的任何建议.

My main goal here is to be able to integrate normal char strings in a Unicode application. Any advice you guys can offer is greatly appreciated.

推荐答案

使用 std::wstring 而不是 C99 变长数组.当前标准保证 std::basic_string 的连续缓冲区.例如，

Use a std::wstring instead of a C99 variable length array. The current standard guarantees a contiguous buffer for std::basic_string. E.g.,

std::wstring wc( cSize, L'#' );
mbstowcs( &wc[0], c, cSize );

C++ 不支持 C99 可变长度数组，因此如果您将代码编译为纯 C++，它甚至无法编译.

C++ does not support C99 variable length arrays, and so if you compiled your code as pure C++, it would not even compile.

随着更改，您的函数返回类型也应该是 std::wstring.

With that change your function return type should also be std::wstring.

记得在main中设置相关的locale.

Remember to set relevant locale in main.

例如，setlocale( LC_ALL, "" ).

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