DOTNET的 - 什么是INT *？ [英] DotNet - What is int*?
问题描述
简单的问题，我导入一个DLL函数，参数都为int *。 当我尝试输入方法（0），我得到一个错误，说：int和INT *不能将
simple question, I import a DLL function and the parameter are int*. When I try to enter Method(0), I get an error which says: "int and int* can not convert".
那是什么意思？
推荐答案
这是一个指向int经典的C表示法。每当类型后跟一个 * ，它指的类型作为的指针那个类型。在C＃中，不像在C，你必须明确定义功能不安全使用指针，除了启用的不安全 code。在项目属性。指针类型也不能直接互换的具体类型，这样类型的引用必须首先考虑。为了得到一个指向另一种类型，如int，在C＃（或C和C ++的这个问题），您必须使用引用操作＆安培; （符号）在变量前面你希望得到一个指向：
That is classic C notation for a pointer to an int. Whenever a type is followed by a *, it denotes that type as a pointer to that type. In C#, unlike in C, you must explicitly define functions as unsafe to use pointers, in addition to enabling unsafe code in your project properties. A pointer type is also not directly interchangeable with a concrete type, so the reference of a type must be taken first. To get a pointer to another type, such as an int, in C# (or C & C++ for that matter), you must use the dereference operator & (ampersand) in front of the variable you wish to get a pointer to:
unsafe
{
int i = 5;
int* p = &i;
// Invoke with pointer to i
Method(p);
}
不安全code C＃
下面是不安全code的一些关键文章，并在C＃中使用指针。
Below are some key articles on unsafe code and the use of pointers in C#.
- Unsafe contexts
- Pointer Types
- Fixed and movable variables
- Pointer conversions
- Pointers in expressions
- The 'fixed' statement
- Stack allocation
- Dynamic memory allocation
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