编程方式访问所有用户开始菜单 [英] Programmatically access All Users Start Menu

问题描述

有谁知道如何以编程方式访问所有用户启动菜单？

Does anyone know how to programmatically access the "All Users" Startup Menu?

在XP中，设在这里：

C:\Documents and Settings\All Users\Start Menu\Programs\Startup

而在Windows 7中，位置为：

And in Windows 7, located here:

C:\ProgramData\Microsoft\Windows\Start Menu\Programs\Startup

具体而言，我有一个安装和部署的项目，我想提出一个快捷方式到应用程序在启动菜单中的所有用户，以便应用程序启动，只要有人登录。

Specifically, I've got a Setup and Deployment project, and I'd like to put a shortcut to the application in the Startup menu for all users so that the application is start whenever anyone logs in.

编辑：<一href="http://www.neowin.net/forum/topic/580258-c%23-get-path-of-start-menu-programs-all-users/page__p__588773578&#entry588773578">I'm pretty的肯定，这就是布莱恩接到了他的答案。

推荐答案

没有对 Environment.GetFolderPath 以正常的方式为所有用户开始菜单中定义的常量，但您可以通过使用Win32 API SHGetSpecialFolderPath 做这种方式：

There is no constant defined for the normal way of Environment.GetFolderPath for the all users start menu, but you can do it this way by using the Win32 API SHGetSpecialFolderPath:

class Program
{
    [DllImport("shell32.dll")]
    static extern bool SHGetSpecialFolderPath(IntPtr hwndOwner,
       [Out] StringBuilder lpszPath, int nFolder, bool fCreate);
    const int CSIDL_COMMON_STARTMENU = 0x16;  // All Users\Start Menu

    static void Main(string[] args)
    {
        StringBuilder path = new StringBuilder(260);
        SHGetSpecialFolderPath(IntPtr.Zero, path, CSIDL_COMMON_STARTMENU, false);
        string s = path.ToString();
    }
}

这篇关于编程方式访问所有用户开始菜单的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！