c编程:将非十进制数字系统转换为十进制的程序 [英] c programming: program to convert non decimal number system to decimal

问题描述

void main()
{
 long n,dec,mult,r,base;
 clrscr();
 printf("\n Enter a base : ");
 scanf("%ld",&base);
 printf("\n Enter a number :");
 scanf("%ld",&n);
 dec = 0;
 mult=1;
 printf("\n Decimal equivalent of base %ld number %ld is ",base,n);
 while ( n != 0 )
 {
  r = n % 10;
  n /= 10;
  r = r * mult;
  dec = dec + r;
  mult *= base;
 } 
 printf("%ld",dec);}

此程序将以2、8和16为基数的任何数字系统的整数部分转换为十进制.请告诉我命令shld b给定2还要计算小数部分.我急需它帮助.

this program converts the integer part of any number system of base 2, 8 &16 to decimal. please tell me wht command shld b given 2 calculate the fractional part also. i need it urgently plz help.

推荐答案

小数点右边的每个数字都是该基数的幂的倒数.因此，对于八进制数字，值0.44等于

Each digit to the right of the decimal point is the reciprocal of the power of the base for that base. So for octal numbers the value 0.44 equates to

0
4 / 8  // .4
4 /64  // . 04

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