将非整数十进制数字转换为二进制 [英] Converting non-integer decimal numbers to binary

问题描述

数据帧输入(DF)

a
123.213
4343.344
3434.43255
422.45
34534

结果以二进制(16位)为必需

results required in binary (16 bits)

我尝试过一个功能

intTobits
rawTobits

但没有为我工作

推荐答案

在

The conversion of integer decimal numbers into binary numbers is thoroughly discussed in this post. Non-integer numbers are a different issue.

对于浮点十进制数字的二进制表示，您可以尝试以下功能:

For the binary representation of floating point decimal numbers you can try this function:

floatToBin <- function(x){
  int_part <- floor(x)
  dec_part <- x - int_part
  int_bin <- R.utils::intToBin(int_part)
  dec_bin <- stringr::str_pad(R.utils::intToBin(dec_part * 2^31), 31, pad="0")
  sub("[.]?0+$", "", paste0(int_bin, ".", dec_bin)) 
}

请注意，此功能仅适用于非负数字.

Note that this function only works for non-negative numbers.

这是问题中指示的数字的输出:

This is the output for the numbers indicated in the question:

nums <- c(123.213, 4343.344, 3434.43255, 422.45, 34534)
sapply(nums, floatToBin)
#[1] "1111011.0011011010000111001010110000001"     
#[2] "1000011110111.010110000001000001100010010011"
#[3] "110101101010.0110111010111011100110001100011"
#[4] "110100110.0111001100110011001100110011001"   
#[5] "1000011011100110"         

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