空指针铸造的问题 [英] Problem with Void Pointer Casting

问题描述

嘿！

我最近一直在研究VC ++中的一种软件，该软件可以与Decive(示波器)进行通信.制造商提供了基于C的库(.h文件和lib x64).
问题在于DLL中的某些功能具有viod指针.这是一些示例.

Hey!

I have been recently working on a software in VC++ that can communicate with a decive (Oscilloscope). The manufacturer provided with Library (.h file and a lib x64) based on C.
The problem is that some of the functions in the DLL have viod pointers. here are a few examples.

#include "CAENDIGITIZER.h"

/**************************************************************************//**
* \param    [IN] waveforms
* \param    [IN] events
******************************************************************************/
CAEN_DGTZ_ErrorCode CAENDGTZ_API CAEN_DGTZ_MallocDPPWaveforms(int handle, void **waveforms, uint32_t *allocatedSize);

CAEN_DGTZ_ErrorCode CAENDGTZ_API CAEN_DGTZ_MallocDPPEvents(int handle, void **events, uint32_t *allocatedSize);

输入参数不是void，而是以下类型的模板:

The input parameters are not void, but are type template of:

typedef struct // for void **events
{
        uint32_t Format;
        uint32_t TimeTag;
    int16_t ChargeShort;
    int16_t ChargeLong;
        int16_t Baseline;
    int16_t Pur;
    uint32_t *Waveforms;
} CAEN_DGTZ_DPP_PSD_Event_t;

typedef struct      //for void **Waveforms
{
    uint32_t Ns;
    uint8_t  dualTrace;
    uint8_t  anlgProbe;
    uint8_t  dgtProbe1;
    uint8_t  dgtProbe2;
    uint16_t *Trace1;
    uint16_t *Trace2;
    uint8_t  *DTrace1;
    uint8_t  *DTrace2;
    uint8_t  *DTrace3;
    uint8_t  *DTrace4;
} CAEN_DGTZ_DPP_PSD_Waveforms_t;

在C语言中，我可以使用一个或多或少像这样的脚本来轻松调用该函数:

In C, i can easily call the function with a script that reads more or less like this:

// main.c
CAEN_DGTZ_DPP_PSD_Event_t       *Events1[MaxNChannels];  // events buffer
CAEN_DGTZ_DPP_PSD_Waveforms_t   *Waveform=NULL;         // waveforms buffer
int AllocatedSize, handle;

public: void progDEVICE()
        /* Allocate memory for the events */
    ret = CAEN_DGTZ_MallocDPPEvents(handle, Events1, &AllocatedSize);
    /* Allocate memory for the waveforms */
    ret = CAEN_DGTZ_MallocDPPWaveforms(handle, &Waveform, &AllocatedSize);
    if (!ret==0) {
        printf("Can't allocate memory buffers\n");
    }
}

由于实时和其他偏好的数据处理量巨大，因此我倾向于使用C ++.但是，问题在于C ++在没有显式强制转换的情况下不喜欢void指针.但我无法一辈子抛弃这些:(
我正在使用VC ++ 2010 Pro. MScompiler和intel编译器只会出现令人讨厌的转换错误.

Due to extremely huge ammount of data processing in realtime and other preferences, I am inclined to use C++. However, the bugger is that C++ donot like void pointers without having an explicit casting. but i am unable to cast these for the life of me:(
I am using VC++2010 Pro. MScompiler and intel Compiler only turn up with nasty casting errors.

error C2664: 'CAEN_DGTZ_MallocDPPEvents' : cannot convert parameter 2 from 'CAEN_DGTZ_DPP_PSD_Event_t *[8]' to 'void **'

我希望有人能帮助我.我没有该库的源代码，只有.h和.lib文件.

非常感谢！
cheers

I was hoping someone can help me out. I donot have the source code of the library, but only the .h and .lib files.

Thanks a Lot!
cheers

推荐答案

//this is your solution:
 ret = CAEN_DGTZ_MallocDPPEvents(handle, (void **)Events1, &AllocatedSize);

顺便说一句，这条线在某些方面很糟糕
由于实时处理大量数据以及其他偏好，我倾向于使用C ++.

by the way, in few ways this line is crappy
Due to extremely huge ammount of data processing in realtime and other preferences, I am inclined to use C++.

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