数字的正则表达式 [英] regular expression for numbers

问题描述

我想使用正则表达式，该正则表达式最多包含0到9之间的10位数字和两位小数.

例如

9999999999.99
0123456789.01
999999
12345

I want to use regular expression which contains maximum 10 digits between 0 to 9 and two decimal places.

e.g.

9999999999.99
0123456789.01
999999
12345

推荐答案

^\d{10}

\ d +(\.\ d { 1 ， 2 })?

\d+(\.\d{1,2})?

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看看此 [

You should have googled first. There are so many links available. :)
Have a look at this[^] also.

此正则表达式可以为您提供所需的输入信息:
\ d {1,10} \.\ d {2} | \ d {1,10}

有关详细信息，请参见:
Expresso-用于构建和测试正则表达式的工具 [ ^ ]

This reguklar expression would give you some input on what you need:
\d{1,10}\.\d{2}|\d{1,10}

For details see this:
Expresso - A Tool for Building and Testing Regular Expressions[^]

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