独立数字正则表达式? [英] Standalone numbers Regex?

问题描述

我目前正在使用此正则表达式:

I currently use this regex:

(\d+)

我可以得到2个字符串的问题:

the problem that i can get 2 strings:

"2112343和4.99"

"2112343 and alot of 4.99"

OR

"4.99和很多2112343"

"4.99 and alot of 2112343 "

我从两个地方都得到了这个

I get this from both:

[2112343, 4, 99]

我只需要获取 2112343 ...我该如何实现?

I need to get only the 2112343... How can i achieve this?

推荐答案

使用环视，您可以将捕获范围限制为仅由其他数字或小数点包围的数字:

Using lookaround, you can restrict your capturing to only digits which are not surrounded by other digits or decimal points:

(?<![0-9.])(\d+)(?![0-9.])

或者，如果您只想匹配独立编号(例如，如果您不想匹配 abc123def 中的123):

Alternatively, if you want to only match stand-alone numbers (e.g. if you don't want to match the 123 in abc123def):

(?<!\S)\d+(?!\S)

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