正则表达式不包含一些单词 [英] Regex for not containing some words

问题描述

大家好.我有一个小问题，我有一些输入文字.我只想匹配该文本，但前提是它不包含某些单词.我知道如何使用字符([^ChArAcTeRsWhItChIdOnTwAnT])做类似的事情.所以我的问题是:有什么方法可以使文本以某些单词开头和某些单词结尾，但该文本不能包含指定的单词?谢谢.

Hi all. I have small problem I have some input text. I want to match that text but only then, when it not contains some words. I know how to do similar thing with characters ([^ChArAcTeRsWhItChIdOnTwAnT]). So my question is: is there any way how to get text starting with some words and ending with some words but that text cannot contain specified word? Thanks.

推荐答案

您想要否定先行或否定先行.假设您要验证，以便短语以"string"开头，以"bee"结尾，但不包含"like".您可以使用此正则表达式(它使用负的超前查询):

You want a negative lookahead or a negative lookbehind. Suppose you want to validate so that a phrase starts with "string" and ends with "bee", but does not contain "like". You could use this regular expression (which uses a negative lookahead):

(?!.*like)^sting.*bee

如果短语包含"like"，则否定的前瞻性将确保该表达式不匹配.例如，像蜜蜂一样s"将是一个匹配项，但像蜜蜂一样ting"将不匹配(因为它包含喜欢").现在，如果要同时禁止"like"和好像"，则修改很简单:

The negative look ahead will ensure that the expression will not match if the phrase contains "like". For example, "sting as if a bee" would be a match, but "sting like a bee" would not match (because it contains "like"). Now, if you want to disallow both "like" and "as if", the modification is simple:

(?!.*(like|as if))^sting.*bee

现在，我上面给出的所有示例短语都不会匹配.

Now neither of the sample phrases I gave above will match.

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