用于匹配不包含单词的行的正则表达式 [英] Regex for matching lines that do NOT contain a word

问题描述

我有以下几行:

消息:Polarion 提交 Mon May 18 06:59:37 CEST 2009消息:Polarion 提交星期五 5 月 15 日 19:39:45 CEST 2009消息:424-18:使用新变量消息:Polarion 提交星期五 5 月 15 日 19:29:10 CEST 2009消息:Polarion 提交星期五 5 月 15 日 19:27:23 CEST 2009消息:000-00:做其他事情消息:Polarion 提交 2009 年 5 月 15 日星期五 17:50:30 CEST消息:401-103:添加了应用程序部分消息:Polarion 提交星期五 5 月 15 日 17:48:46 CEST 2009消息:Polarion 提交星期五 5 月 15 日 17:42:04 CEST 2009

我想得到所有不包含Polarion"的行

我该怎么做?

ps:我看到了:正则表达式匹配不是特定的东西子串但这对我没有帮助

pps:我正在尝试在 tortoiseSVN 中执行此操作以选择日志消息，并且我认为负向后视"存在问题

解决方案

这个表达式将完成这项工作.

^(?:.(?

它使用零宽度负后视断言来断言该字符串不包含Polarion".

<前>^ 锚定到字符串的开头(?: 非捕获组.匹配任何字符(?<!Polarion) 零宽度负回顾断言 - 文本到当前位置的左边不能是Polarion")* 零次或多次$ 锚定到字符串末尾

以下版本只会在n"之后执行断言 - 也许这会更快，也许更慢.

^(?:[^n]*|n(?<!Polarion))*$

i have the following lines:

Message:Polarion commit Mon May 18 06:59:37 CEST 2009
Message:Polarion commit Fri May 15 19:39:45 CEST 2009
Message:424-18: use new variable
Message:Polarion commit Fri May 15 19:29:10 CEST 2009
Message:Polarion commit Fri May 15 19:27:23 CEST 2009
Message:000-00: do something else
Message:Polarion commit Fri May 15 17:50:30 CEST 2009
Message:401-103: added application part
Message:Polarion commit Fri May 15 17:48:46 CEST 2009
Message:Polarion commit Fri May 15 17:42:04 CEST 2009

and i want to get all the lines NOT containing "Polarion"

how would i do this?

ps: i saw: Regex to match against something that is not a specific substring but it doesn't help me

pps: i'm trying to do this in tortoiseSVN to select log messages, and i think there is a problem with "negative lookbehind"

解决方案

This expresion will do the job.

^(?:.(?<!Polarion))*$

It uses a zero-width negative lookbehind assertion to assert that the string does not contain "Polarion".

    ^                  Anchor to start of string
    (?:                Non-capturing group
        .              Match any character
        (?<!Polarion)  Zero-width negative lookbehind assertion - text to the
                       left of the current position must not be "Polarion"
    )
    *                  Zero or more times
    $                  Anchor to end of string

The following version will perform the assertion only after a 'n' - maybe this will be faster, maybe slower.

^(?:[^n]*|n(?<!Polarion))*$

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