为什么？使用意图我无法播放下载的MP4视频文件 [英] Why? I can't play downloaded mp4 video file using Intent

问题描述

我要开发一个应用程序中，我下载从URL视频文件
下载后，我打它通过一个意图。

但我得到相同的消息，每次：你无法播放此视频

下载code：

 保护字符串doInBackground（字符串... PARAMS）{    档案文件=新的文件（getFilesDir（），generateFileName（PARAMS [0]））;
        尝试{
            URL U =新的URL（PARAMS [0]）;
            康涅狄格州的URLConnection = u.openConnection（）;
            INT CONTENTLENGTH = conn.getContentLength（）;            DataInputStream以流=新DataInputStream所（u.openStream（））;            字节[]缓冲区=新的字节[CONTENTLENGTH]
            stream.readFully（缓冲液）;
            stream.close（）;            DataOutputStream类FOS =新DataOutputStream类（新的FileOutputStream（文件））;
            fos.write（缓冲液）;
            fos.flush（）;
            fos.close（）;        }赶上（FileNotFoundException异常五）{
            e.printStackTrace（）;
        }赶上（IOException异常五）{
            e.printStackTrace（）;
        }        返回null;
 }
 

播放视频的方法：

 公共无效的playVideo（字符串文件名）{       乌里数据= Uri.parse（新文件（文件名）.getAbsolutePath（））;
       Log.i（DATA：，+数据）;       意向意图=新的Intent（）;
       intent.setAction（android.content.Intent.ACTION_VIEW）;
       intent.setDataAndType（数据，视频/ MP4）;
       startActivity（意向）;
}
 

解决方案

这code到意向提供额外的信息来源时为我工作。这不是视频数据，但图像数据，但我相信这个概念应该是相同的（我可能是错的，因为我没有尝试这个视频）。

 文件文件=新的文件（getExternalFilesDir（空），image.png）;
字符串uriPath =文件：//+ file.getPath（）;
shareIntent.putExtra（Intent.EXTRA_STREAM，Uri.parse（uriPath））;
 

请注意，我提供给意向图像这门课程之前下载，然后保存在应用程序的目录（这个我getExternalFilesDir得到（空））。然后将图像传送到一个​​意图作为流。

如果这没有帮助，那么你或许检查是否安装了可以处理您的视频类型的任何应用程序（它是MP4或者是什么格式？）

I have to develop an application in which I am downloading a video file from an URL After downloading, I am playing it through an Intent.

But every time I am getting the same message: "You can't play this video."

download code:

protected String doInBackground(String... params) {

    File file = new File(getFilesDir(), generateFileName(params[0]));
        try {
            URL u = new URL(params[0]);
            URLConnection conn = u.openConnection();
            int contentLength = conn.getContentLength();

            DataInputStream stream = new DataInputStream(u.openStream());

            byte[] buffer = new byte[contentLength];
            stream.readFully(buffer);
            stream.close();

            DataOutputStream fos = new DataOutputStream(new FileOutputStream(file));
            fos.write(buffer);
            fos.flush();
            fos.close();

        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        return null;
 }

method for playing the video:

public void playVideo(String fileName) {

       Uri data = Uri.parse(new File(fileName).getAbsolutePath());
       Log.i("DATA: ",""+data);

       Intent intent = new Intent();
       intent.setAction(android.content.Intent.ACTION_VIEW);
       intent.setDataAndType(data, "video/mp4");
       startActivity(intent); 
}

解决方案

This code worked for me when supplying extra infomation to an intent. It's not video data, but image data, but I believe the concept should be the same (I could be wrong, since I didn't try this on video).

File file = new File(getExternalFilesDir(null), "image.png");
String uriPath = "file://"+file.getPath(); 
shareIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse(uriPath));

Note that the image I am supplying to the intent is downloaded before this of course and then saved in the directory of the app (this I get with getExternalFilesDir(null)). Then the image is passed to an intent as a stream.

If this does not help you then maybe check if there are any apps installed that can handle your type of video (is it mp4 or what is the format?)

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