如何处理回发事件 [英] how to handle post back event

问题描述

在page_load事件中创建动态链接按钮和标签.标签显示数据库值，链接按钮是从数据库中删除记录.每个标签控制一个删除按钮.当我单击特定记录的删除按钮时，记录已成功删除，但已删除的记录显示在页面上.我希望删除的记录不显示在页面上.

i m create dynamically link button and label at page_load event. label display the database value and link button is to delete record from database.every label control one delete button. when i m click on delete button of specific record the record is deleted successfully but deleted record display on page. i want deleted record not to display on page .

推荐答案

您可以将记录的ID设置为标签的ID！
然后将您的记录放在面板或每个可以有子控件的控件中！
并在删除记录后将其写入您的代码:

you can set the ID of the record to ID of your label!
then put your records in a panel or every control that can have child control!
and just after deleting the record write this to your code:

Panel.Controls.Remove(label.ID);

我认为您是在谈论Gridview -Item Template- Event bubbling.如果是，则只需在该删除操作之后重新绑定Gridview.查看本教程以获取更多详细信息使用GridView控件更新，删除记录 [

I think you''re talking about Gridview - Item Template - Event bubbling. If yes then just Rebind the Gridview after that delete operation. Check this tutorial for more details Updating, Deleting records using GridView control[^]

您需要在删除后调用绑定代码. ..

you need to call binding code after deleting....

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