回发两次如何处理 [英] Post back twice How to handle it

问题描述

我正在使用带有ajax选项卡的``ascx''控件

当我单击下拉菜单或任何服务器控件(如按钮，下拉菜单等)的"asp:button"或"selected change"事件时，每个控件都会发回两次.

为什么会发生?

它应该像往常一样回发1次

可能是什么问题?

需要帮助

没有JavaScript或ajax用于提交表单

I am using ''ascx'' control with ajax tab

When I click the ''asp:button'' or ''selected change'' event of drop down or any server control like button, drop down etc, every control posts back twice.

Why its happening?

It should post back 1 time as it usually happens

What could be the issue?

Need Help

No JavaScript or ajax used to submit form

推荐答案

如果您具有执行document.formName.submit()的javascript函数，并且具有在提交时具有提交按钮的表单单击提交，表单将被提交两次.一种避免这种情况的简单方法是将提交按钮的类型从提交"更改为按钮"，然后只有javascript函数将提交表单.

祝你好运！

If you have a javascript function which does document.formName.submit() and a form that has a submit button when you click on submit the form will be submitted twice. A simple way to avoid that it is to change the type of the submit button from "submit" to "button" then only the javascript function will submit the form.

Good luck!

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