下拉回发两次 [英] Dropdown postback twice

问题描述

我在"ddl_SelectedIndexChanged"上放置了一个断点.
我意识到...代码被调用了两次.这会影响我有用的功能.

注意:由于某些原因，我无法使用UpdatePanel.

我的代码类似于以下内容:

I have place a break-point on ''ddl_SelectedIndexChanged''
I realize...code is calling twice. This effects my useful functionality.

Note: I can not use UpdatePanel because of some reason.

My code is similar to below:

$(document).ready(function(){
    SetOnChange();
});
var fieldChange=false;
var postBack='0';
function SetOnChange()
{
    var $inputs = $("#aspnetForm :input");
    $inputs.each(function() {
        if(this.id.indexOf('__')<0)
        {
            if(this.id.indexOf('_ddl')>0 && this.className.indexOf('post')>0)
            {
                $(this).change(function() { postBack='1'; });
            }
            else
            {
                $(this).change(function() { 
                    fieldChange=true;
                });
            }
        }
    });
}

<asp:DropDownList ID="ddl" TabIndex="1" runat="server" CssClass="dropdowns post"

                                                                                    Style="width: 290px;" AutoPostBack="true" OnSelectedIndexChanged="ddl_SelectedIndexChanged" >
                                                                                </asp:DropDownList>

protected void ddl_SelectedIndexChanged(object sender, EventArgs e)
        {
//some code here
        }

请帮忙.预先表示感谢.

Please help. Thanks in advance.

推荐答案

(文档).ready(功能(){ SetOnChange(); }); var fieldChange = false ; var postBack = ' 0'; 函数 SetOnChange() { var

(document).ready(function(){ SetOnChange(); }); var fieldChange=false; var postBack='0'; function SetOnChange() { var

inputs =

( " );

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