如何获取出生日期值到数据库 [英] how get Date of birth value to database
本文介绍了如何获取出生日期值到数据库的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我如何通过我的注册页面将这个生日函数值发布到我的数据库中?请帮忙 !!任何其他建议,我都需要在我的php表单中添加三项.
how i can post this date of birth function value to my database through my registration page? Please help !! Any other suggestions, i need three drop down in my php form.
<?
function date_dropdown($year_limit = 0){
$html_output = ' <div id="date_select" >'."\n";
$html_output .= ' <label for="date_day"></label>'."\n";
/*days*/
$html_output .= ' <select name="date_day" id="day_select">'."\n";
for ($day = 1; $day <= 31; $day++) {
$html_output .= ' <option>' . $day . '</option>'."\n";
}
$html_output .= ' </select>'."\n";
/*months*/
$html_output .= ' <select name="date_month" id="month_select" >'."\n";
$months = array("", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December");
for ($month = 1; $month <= 12; $month++) {
$html_output .= ' <option value="' . $month . '">' . $months[$month] . '</option>'."\n";
}
$html_output .= ' </select>'."\n";
/*years*/
$html_output .= ' <select name="date_year" id="year_select">'."\n";
for ($year = 1900; $year <= (date("Y") - $year_limit); $year++) {
$html_output .= ' <option>' . $year . '</option>'."\n";
}
$html_output .= ' </select>'."\n";
$html_output .= ' </div>'."\n";
return $html_output;
}
?>
html form code:
<td> // or add date of birth age condition in ()
echo date_dropdown();
?>
</td>
推荐答案
year_limit = 0){ span>
year_limit = 0){
html_output > < div id =" date_select>' ."\ n"; span>
html_output = ' <div id="date_select" >'."\n";
html_output > =' ."\ n"; span> /*天数*/ span>
html_output .= ' <label for="date_day"></label>'."\n"; /*days*/
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