陈述时提供帮助 [英] Help in if statemment

问题描述

if(x&1)！= 0


该语句如何工作?
我不明白

if(x & 1) != 0


how does the statement work?
i can''t get it
any help please??

推荐答案

它将检查x的第一位(最低有效位)是否已设置(等于1，而不是0).
只有语法需要方括号括起来:if ((x & 1) != 0) ….

—SA

It checks up if the first (least-significant) bit of x is set (equals to 1, not to 0).
Only the syntax requires brackets around to condition: if ((x & 1) != 0) ….

—SA

这是按位操作.有关更多信息，请参见此处:
http://www.leepoint.net/notes-java/data/expressions/bitops.html [^ ]
因此，x& 1检查是否设置了第一位，x& 2检查是否设置了第二位，依此类推...

This is a bitwise operation. See here for more information:
http://www.leepoint.net/notes-java/data/expressions/bitops.html[^]
So, x&1 checks if the first bit is set, x&2 checks if the second bit is set and so on...

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