在进行浮点计算时，所有常量都是双精度的而不是整数的吗? [英] When doing floating point calculations, are all constants doubles rather than integers?

问题描述

进行浮点计算时，所有常量都是双精度的而不是整数的吗?
why

When doing floating point calculations, are all constants doubles rather than integers?
why

推荐答案

否.但是在进行计算之前，它们将隐式转换为两倍.如果不是这样，系统将很难进行计算.
写完全是有效的

No. But they would be implicitly cast to a double before the calculation went ahead. If they weren''t, the calculation would be much harder for the system to do.
It is perfectly valid to write

double d = 10.3445;
double result = d * 17;
int i = 17;
double result2 = d * i;

在这两种情况下，整数都会在乘法发生之前转换为双精度.

In both cases the integer will be cast to a double before the multiplication occurs.

当计算机计算浮点表达式时，它首先将所有值转换为浮点值.

When the computer evaluates a floating point expression, it first converts all the values to floating ones.

是的，
有关更多详细信息，请参见浮桥表示法.

Yes,
for further details see the floating pont representation.

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