计算双精度数组中所有元素的总和 [英] calculate the sum of all element in a double array

问题描述

我在使用数组进行递归时有点困惑，有人可以纠正我的错误吗?

i am a bit confused in using array in doing recursion, can anyone correct my mistake?

新更新，根据需要提供的问题，某些行无法编辑

new update, based on question required some of the line cannot be edit

double sum_of_array(double x[],int size)
{
    static double sum; <---can be edit
    int index = 0; <--can be edit

    if(index<size){
        return sum + sum_of_array(x,size-1); <--can be edit
    } else {
       something ; <--can be edit
       return sum; <--can be edit
    }
}

int main(void){
    double x[] = {4.5,5.0,6.8};
    double y[] = {4.7,3.4,2.5,5.2};

    cout<<"Sum X = "<<sum_of_array(x,3)<<endl;
    cout<<"Sum Y = "<<sum_of_array(y,4)<<endl;

    return 0;
}

输出:

Sum of the element in X[]=15.3

Sum of the element in Y[]= 15.8

推荐答案

您从未真正将 x [] 和 y [] 中的值添加到 sum，此外， index 始终等于 0 .您可能应该将它作为另一个参数传递给函数:

You never actually add the values in x[] and y[] to sum and in addition, index is always equal to 0. You should probably pass it as another parameter to the function:

double sum_of_array(double x[], int size, int index)
{
    if(index<size){
        return x[index] + sum_of_array(x, size, index+1); 
    }
    else {
        return 0;
    }
}

您实际上并不需要 sum 变量.

You don't actually need the sum variable.

这篇关于计算双精度数组中所有元素的总和的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！