在一个实现viewpager片段获得的getString（） [英] Access to getString() in a fragment that implements a viewpager

问题描述

我使用使用SherlockFragment嵌套的片段，一切工作正常。但我不能够使viewpager标题字符串，这样我可以使用string.xml支持多国语言。

I am using a nested fragment using SherlockFragment, all works fine. But i am not being able to make viewpager title to string so that i can support multilanguage using string.xml.

下面是我的code

public class schedule_pl  extends SherlockFragment {


private static String titles[] = new String[] { "Portugal", "Lisbon" , "Azores" };

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    View view = inflater.inflate(R.layout.main_pager, container, false);
    // Locate the ViewPager in viewpager_main.xml
    ViewPager mViewPager = (ViewPager) view.findViewById(R.id.viewPager);
    // Set the ViewPagerAdapter into ViewPager
    mViewPager.setAdapter(new MyAdapter (getChildFragmentManager()));
    return view;
}

@Override
public void onDetach() {
    super.onDetach();
    try {
        Field childFragmentManager = Fragment.class
                .getDeclaredField("mChildFragmentManager");
        childFragmentManager.setAccessible(true);
        childFragmentManager.set(this, null);
    } catch (NoSuchFieldException e) {
        throw new RuntimeException(e);
    } catch (IllegalAccessException e) {
        throw new RuntimeException(e);
    }
}


public static class MyAdapter extends FragmentPagerAdapter {

    public MyAdapter(FragmentManager fm) {
        super(fm);
    }


    @Override
    public Fragment getItem(int position) {
        switch(position)
         {
              case 0:
                  return new place();
              case 1:   
                  return new place2();               
              case 2:
                  return new place3();

    }
        return null;
        }




    @Override
    public CharSequence getPageTitle(int position) {
        return titles[position];
    }

    @Override
    public int getCount() {
        // Show 3 total pages.
        return 3;
    }  
    }


public static class place extends Fragment {

    public place() {
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {
        View rootView = inflater.inflate(R.layout.fragment1, container,
                false);
        return rootView;
    }
}
public static class place3 extends Fragment {

    public place3() {
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {
        View rootView = inflater.inflate(R.layout.fragment2, container,
                false);
        return rootView;
    }
}
public static class place2 extends Fragment {

    public place2() {
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {
        View rootView = inflater.inflate(R.layout.fragment3, container,
                false);
        return rootView;
    }
}

}

在getPageTitle我可以在工作与串并已经尝试过多种方法。

on getPageTitle i can't that working with strings and already tried several methods.

<一个href=\"http://stackoverflow.com/questions/14112628/access-to-getstring-in-android-support-v4-app-fragmentpageradapter\">Access给GetString（）在android.support.v4.app.FragmentPagerAdapter？
这是在网站上类似的问题，但没有回答让我在​​正确的道路上。

Access to getString() in android.support.v4.app.FragmentPagerAdapter? This is a question similar on the site but neither answer got me on the right path.

我试图用这样的：

@Override
    public CharSequence getPageTitle(int position) {
        Locale l = Locale.getDefault();
        switch (position) {
        case 0:
            return getcontext.getString(R.string.title_section_schedule1).toUpperCase(l);
        case 1:
            return getcontext.getString(R.string.title_section_schedule2).toUpperCase(l);
        case 2:
            return getcontext.getString(R.string.title_section_schedule3).toUpperCase(l);
        }
        return null;
    }

但不起作用。任何人都知道解决这个？

But do not work. Anyone knows the solution to this?

推荐答案

您可以在活动传递到适配器构造函数。

You can pass the Activity to your adapter constructor.

mViewPager.setAdapter(new MyAdapter (getChildFragmentManager(), getActivity()));

然后 MyAdapter ：

//declare a private variable for the activity
private Activity myActivity;
public MyAdapter(FragmentManager fm, Activity myActivity) {
    super(fm);
    this.myActivity = myActivity;
}

然后在 getPageTitle

...
return myActivity.getString(R.String.title_section_scheduale1).toUpperCase(l);
...

试试吧希望它为你工作。

Try it out hope it works for you.

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