正则表达式可忽略注释行 [英] Regular Expression to ignore commented lines

问题描述

我正在尝试创建正则表达式来解析一段代码.

这是我的代码snipett

 Method1( 100 ，variable1)

  @"  

从上面的表达式中，我正在提取不同的数据.

但是在某些情况下，我有机会发表评论
如下所示

 Method1( 100 ，variable1)' 解决方案

"

从上面的表达式中，我正在提取不同的数据.

但是在某些情况下，我有机会发表评论
如下所示

 Method1( 100 ，variable1)'  字符串模式=  @"  ^ \ s * Method1 \ s * \(\ s *(\ d +)\ s *，\ s *([^)] *)\)(\ s * \'.*)?\ s * 

I am trying to create regular expression to parse a piece of code.

here is my code snipett

Method1(100,variable1)

@"^(?\Method1)\((?\d+),\s(?\w+)\)$"

from above expression i am extracting different data.

But i some cases there are chances to commented lines
like below

Method1(100,variable1) 'method1 is called here

so how what should i add in my above regular expression to ignore strings after the '')'' close bracket

解决方案

"

from above expression i am extracting different data.

But i some cases there are chances to commented lines
like below

Method1(100,variable1) 'method1 is called here

so how what should i add in my above regular expression to ignore strings after the '')'' close bracket

You can try the regular expression

''/\*([^*]|[\r\n]|(\*([^/]|[\r\n])))*\*/''

to ignore comments in the code

Here it is :

string pattern = @"^\s*Method1\s*\(\s*(\d+)\s*,\s*([^)]*)\)(\s*\'.*)?\s*

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