从指定的日期时间比较当前的日期时间 [英] Compare current DateTime from Specified DateTime

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问题描述



我的表中有两个字段.一个是startTime&另一个是Endtime.
我想确定从屏幕输入的时间是否在数据库开始时间&之间;时间结束 .

Hi

i have two fields in my Table . one is startTime & other is Endtime .
I want to find whether the input time from screen lies in between the DB starttime & End Time .

Sample DB Values 
StartTime ENDTime 
8.00      15.00


假设用户在屏幕上输入10.00.现在,我需要检查输入的时间是否介于开始时间和开始时间之间.结束时间.


Suppose the user enter 10.00 in screen . now i need to check whether the entered time lies in between start & end time .

推荐答案

您可以使用BETWEEN比较来测试时间.例如,考虑以下内容:
You can use the BETWEEN comparison to test the time. For example, consider the following:
declare @start as time
declare @end as time
declare @test1 as time
declare @test2 as time
begin
 set @start = cast('08:00' as time)
 set @end = cast('15:00' as time)
 set @test1 = cast('10:00' as time)
 set @test2 = cast('20:00' as time)
 if @test1 between @start and @end begin
    print '@test1 is between';
 end;
 if @test2 between @start and @end begin
    print '@test2 is between';
 end;
end;
go


两者之间可以在查询中用作条件等.如果使用日期时间,则必须剥离日期部分.例如:


The between can be used in a query as a condition etc. If you''re using a datetime then you have to strip off the date portion. For example:

select cast(getdate() as time)


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