日期/时间比较 [英] Date/time comparison

问题描述

我想找到记录之间的最小日期/时间的日期/时间.在具有多个记录的表中.

I want to find the date/time with minimum date/time between records. In a table with multiple records.

Fx.

 - 11/11-15 13:00
 - 11/11-15 15:30
 - 11/11-15 16:45 <= (find this record)
 - Timenow (11/11-15 18:33) the current record i want to create but i need to compare the old dates with.

我无法创建逻辑，帮助！

I can't create the logic, help !

谢谢

推荐答案

您可以创建一个函数，该函数返回两个日期之间的差额，通过该函数运行所有可能的日期，然后选择最小的差额.

You can create a function that returns the difference between two dates, run all the possible dates through this function, then pick the lowest difference.

类似这样的东西(伪C代码)

Something like this (pseudo c code)

 int array[numdates];
 for (int i=0;i<numdates;i++)
     array[i]=compareDates(date[index], currentDate);

然后，您可以对数组进行排序，以便最小的数字在开头(或结尾)并返回该数字.

Then you can sort the array so the lowest number is at the beginning (or end) and return that one.

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