我无法获得正确的输出 [英] I can't get the right output

问题描述

#include <stdio.h>
 
void getInput(int* pNum1, int* pNum2);
void calc(int num1, int num2, int* pSum, int* pQuotient, int* pRemainder,
double* pHalfNum1, double* pHalfNum2, double* pFraction, int* pAlgebraic);
int intOps(int num1, int num2, int* pSum, int* pQuotient, int* pRemainder);
double doubleOps(int num1, int num2, double* pHalfNum1, double* pHalfNum2,
double* fraction);
int algebra(int num1, int num2);
void display(int num1, int num2, int sum, int quotient, int remainder,
double halfNum1, double halfNum2, double fraction, int algebraic);
 
 
int main(void)
{
   int num1, num2;
   int sum, quotient, remainder;
   double halfNum1, halfNum2, fraction;
   int algebraic;
 
 
   getInput(&num1, &num2);
   calc(num1, num2, &sum, "ient, &remainder, &halfNum1, &halfNum2,
   &fraction, &algebraic);
   display(num1, num2, sum, quotient, remainder,halfNum1, halfNum2,
   fraction, algebraic);
 
 
   return 0;
}
 
 
void getInput(int* pNum1, int* pNum2)
{
   printf("\nPlease enter two integers : ");
   scanf("%d%d", pNum1, pNum2);
}
 
void calc(int num1, int num2, int* pSum, int* pQuotient, int* pRemainder,
double* pHalfNum1, double* pHalfNum2, double* pFraction, int* pAlgebraic)
{
   intOps(num1, num2, pSum, pQuotient, pRemainder);
   doubleOps(num1, num2, pHalfNum1, pHalfNum2, pFraction);
   algebra(num1, num2);
}
 
 
int intOps(int num1, int num2, int* pSum, int* pQuotient, int* pRemainder)
{
   *pSum = num1 + num2;
   *pQuotient = num1 / num2;
   *pRemainder = num1 % num2;
}
 
 
double doubleOps(int num1, int num2, double* pHalfNum1, double* pHalfNum2,
double* pFraction)
{
   *pHalfNum1 = num1 / 2.0;
   *pHalfNum2 = num2 / 2.0;
   *pFraction = num1 / (double)num2;
}
 
 
int algebra(int num1, int num2)
{
   int algebraic;
   int x, y;
   x = num1;
   y = num2;
   algebraic = (2 * x) + (4 * y) + (x * y) - (x / y);
   return algebraic;
}
void display(int num1, int num2, int sum, int quotient, int remainder,
double halfNum1, double halfNum2, double fraction, int algebraic)
{
   printf("\n%20s%20s", "Description", "Data");
   printf("\n%20s%20s", "-----------", "----");
   printf("\n%20s%20d", "Input 1", num1);
   printf("\n%20s%20d", "Input 2", num2);
   printf("\n%20s%20d", "Sum", sum);
   printf("\n%20s%20.1lf", "Half of input 1", halfNum1);
   printf("\n%20s%20.1lf", "Half of input 2", halfNum2);
   printf("\n%20s%20d", "Quotient", quotient);
   printf("\n%20s%20d", "Remainder", remainder);
   printf("\n%20s%20.4lf", "Fraction", fraction);
   printf("\n%20s%20d", "Algebra", algebraic);
   printf("\n\n");
}


</stdio.h>

这是我的代码.除代数方法外，它可以编译并正确运行.那总是返回0的结果.我在做什么错?

This is my code. It compiles and runs correctly except for the algebra method. That always returns a result of 0. What am i doing wrong?

推荐答案

您不将algebra的结果存储在任何地方
我想您想将algebra(num1, num2);行更改为*pAlgebraic = algebra(num1, num2);

you do not store the result of algebra anywhere
I guess you want to change the line algebra(num1, num2); to *pAlgebraic = algebra(num1, num2);

您在calc中的其他两个函数通过接受您答案的指针传递变量:

Your two other functions in calc are passing in variables by pointer that accept your answers:

<br />
int intOps(int num1, int num2, int* pSum, int* pQuotient, int* pRemainder)<br />
{<br />
   *pSum = num1 + num2;<br />
   *pQuotient = num1 / num2;<br />
   *pRemainder = num1 % num2;<br />
}<br />
<br />
double doubleOps(int num1, int num2, double* pHalfNum1, double* pHalfNum2,<br />
double* pFraction)<br />
{<br />
 *pHalfNum1 = num1 / 2.0;<br />
   *pHalfNum2 = num2 / 2.0;<br />
   *pFraction = num1 / (double)num2;<br />
}<br />

这就是他们存储答案以打印出来的方式.

您的Algegra函数接受值，计算结果并适当地返回结果

That is how they are storing the answers to print out.

your Algegra function takes in the values, calculates the result, and returns the result appropriately

<br />
int algebra(int num1, int num2)<br />
{<br />
  ...<br />
  return algebraic;<br />
}<br />

但是，当您在函数calc中调用它时，结果不会存储到预期的字段中.

代数(num1，num2);

就像第一个答案所建议的那样，您将需要将呼叫更改为:

*pAlgebraic = algebra(num1, num2);

在进行更改以更正此问题之前，请在algebra函数中放置另一个printf实例进行测试，您将看到正确的答案:

printf("\ n％20s％20d"，代数内部的结果"，代数);

此致
保罗

However, when you call it in the function calc, the result is not stored off into the intended field.

algebra(num1, num2);

Like the first answer suggests, you will want to change the call to this:

*pAlgebraic = algebra(num1, num2);

Before you make the change to correct this, place another instance of your printf to test with, in the algebra function, and you will see the correct answer:

printf("\n%20s%20d", "result inside of Algebra", algebraic);

Regards,
Paul

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