如何在C#中生成警报 [英] how to generate an alarm in C#

问题描述

如何在频率在800hz/970hz之间变化并且周期每秒重复两次的C#中生成警报

how to generate an alarm in C# where frequence varied between 800hz/970hz and where the cycle is repeated 2 times every second

推荐答案

我知道更简单的方法:

I know much simpler way:

for (int index=0; index<repetitions; ++index)
{
    System.Console.Beep(800, 250);
    System.Console.Beep(970, 250);
    //frequency (first parameter) and timing (second parameter) may vary :-)
}

注释:

您没有解释频率调制的概况；这是最简单的变体之一.

您可能需要在单独的线程中运行它-可以工作.

您无需使您的应用程序成为控制台应用程序.此代码将在任何应用程序中运行.

-SA

Notes:

You did not explain the profile of frequency modulation; this is one of the simplest variants.

You may want to run it in a separate thread — it will work.

You don''t need to make you application a console application. This code will run in any application.

—SA

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已在此问题中进行了讨论

在C#中使用采样频率 [

Has been discussed in this Question

Use of sampling frequency in C#[^]

might be helpful :)

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