如何在C#中生成随机字符串? [英] How to Generate Random String in C#?

问题描述

嗨
我想生成随机值，例如344298-5FCD-477C-A5AE-930596C.
当我单击按钮时，我想生成新值..


预先感谢，
Pawan.

Hi
I want to generate random value like 344298-5FCD-477C-A5AE-930596C.
when i click on button i want generate new value..


Thanks in advance,
Pawan.

推荐答案

如果您是指GUID，请使用System.GUID.NewGuid().

如果要生成的字符串/值不是GUID，则需要编写自己的逻辑(使用Random() 类).

If you mean a GUID, then use System.GUID.NewGuid().

If the string/value you want to generate is not a GUID, you will need to write your own logic (using the Random() class).

int patternsNum = 3;// the number of string serial want to create example 5: 44850-rt64x-xFtmt-tyuxu-cbhyt6
           int patternLength = 3; // the lenght of each pattern example 4: xtry
           string[] buff = new string[3];

           string patt = "";
           int xx = 64;
           for (int i = 0; i < patternsNum; i++)
           {
               patt = "";
               for (int j = 0; j < patternLength; j++)
               {
                   Random pat = new Random(64);
                   int inte = xx + pat.Next(32) ;
                   xx = inte+Convert.ToInt16(DateTime.Now.Second);
                   char ch = Convert.ToChar(inte);
                   patt += ch.ToString();
               }
               buff[i] = patt;
           }

           // out:
           foreach (string x in buff)
           {
               MessageBox.Show(x);
           }

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