如何在 Ruby 中生成随机字符串 [英] How to generate a random string in Ruby

问题描述

我目前正在为 "A" .. "Z" 生成一个 8 字符的伪随机大写字符串:

I'm currently generating an 8-character pseudo-random uppercase string for "A" .. "Z":

value = ""; 8.times{value  << (65 + rand(25)).chr}

但它看起来并不干净，并且不能作为参数传递，因为它不是单个语句.为了得到混合大小写的字符串 "a" .. "z" 加上 "A" .. "Z"，我将其更改为:

but it doesn't look clean, and it can't be passed as an argument since it isn't a single statement. To get a mixed-case string "a" .. "z" plus "A" .. "Z", I changed it to:

value = ""; 8.times{value << ((rand(2)==1?65:97) + rand(25)).chr}

但它看起来像垃圾.

谁有更好的方法?

推荐答案

(0...8).map { (65 + rand(26)).chr }.join

我花太多时间打高尔夫球.

I spend too much time golfing.

(0...50).map { ('a'..'z').to_a[rand(26)] }.join

最后一个更令人困惑，但更灵活，浪费的周期更少:

And a last one that's even more confusing, but more flexible and wastes fewer cycles:

o = [('a'..'z'), ('A'..'Z')].map(&:to_a).flatten
string = (0...50).map { o[rand(o.length)] }.join

如果您想生成一些随机文本，请使用以下内容:

If you want to generate some random text then use the following:

50.times.map { (0...(rand(10))).map { ('a'..'z').to_a[rand(26)] }.join }.join(" ")

此代码生成 50 个单词长度小于 10 个字符的随机单词字符串，然后用空格连接

this code generates 50 random word string with words length less than 10 characters and then join with space

这篇关于如何在 Ruby 中生成随机字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！